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nadezda [96]
3 years ago
11

How to solve 7+3=4+_

Mathematics
1 answer:
andrey2020 [161]3 years ago
8 0
7+3=4+6 Both numbers equal 10
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A hardware store sells light bulbs in different quantities. the graph shows the cost of various quantities. according to the gra
skelet666 [1.2K]

Looking at the two black dots

5 bulbs cost $9

Divide total cost by number of bulbs bought:

9 / 5 = $1.80 per bulb.

10 bulbs cost $18

Divide total cost by number of bulbs bought:

18 / 10 = $1.80 per bulb

The cost for one bulb is $1.80

3 0
3 years ago
A middle school has the fifth and sixth grades. There are 100 fifth-grade boys and 110 fifth-grade girls. There are 7 fewer sixt
Mama L [17]

The ratio of girls to boys in the middle school = 213 : 193

Number of fifth-grade boys = 100

Number of fifth grade girls = 110

There are 7 fewer sixth-grade boys than fifth-grade boys

Number of sixth-grade boys = 100 - 7

Number of sixth-grade boys = 93

There are 10 more sixth-grade girls than sixth-grade boys

Number of sixth-grade girls = 93 + 10

Number of sixth-grade girls = 103

Total number of girls = Number of sixth-grade girls + Number of fifth-grade girls

Total number of girls = `103 + 110

Total number of girls = 213

Total number of boys = Number of sixth-grade boys + Number of fifth-grade boys

Total number of boys = `93 + 100

Total number of boys = 193

The ratio of girls to boys in the middle school = 213 : 193

Learn more on ratio here: brainly.com/question/25927869

4 0
2 years ago
Which unit of measurement would you use to measure? write cups, pint, quart.
BartSMP [9]
1. Pint
2. cups
3. quart
4. cups
3 0
3 years ago
Read 2 more answers
What is the product of 9 radical 5 and 5 radical 10 in simplest radical form?
tatuchka [14]

Answer:

Step-by-step explanation:

(9√5)   (5√10)

The leading interger product is found by multiplying 9 and 5

The leading integer product is 9*5 = 45

The radical product is (√5*10

Factor 10

radical product = √5*2*5

There are 2 fives underneath the radical. Take one out and ignore the other

radical product = 5√2

The 5 now multiplies by 45 and √2 becomes part of the answer

5*45√2

225√2

3 0
2 years ago
Can somebody please walked through this, I'm so confused and I have a test in 6 hours...
erastova [34]

Answer:

Q3: x = 4, y = 4, z = 4

Q4: x = 6, y = 0, z = -4

Step-by-step explanation:

Question 3: Simultaneous equations requires us to solve for x, y and z.

Since all three equations have a z in them, I will first solve for z.

Substitute in the first and third equation into the second equation.

First equation: x = 5z - 16

Second Equation: -4x + 4y - 5z = -20

Third equation: y = -z + 8

Substituting in x = 5z - 16 and y = -z + 8 for the x and y in the second equation.

-4(5z - 16) + 4(-z + 8) - 5z = -20

Expand

-20z + 64   - 4z + 32   - 5z = -20

Simplify and solve for z by putting all the numbers on one side and all the z's on the other side of the equals

-20z - 4z - 5z = -20 - 32 - 64

-29z = -116

z = -116/-29

z = 4

Substitute in this z value into the first and last equation and then solve for x and y

x = 5z - 16

x = 5(4) - 16

x = 20 - 16

x = 4

And

y = -z + 8

y = -(4) + 8

y = 4 (Its just a coincidence that they all equal to 4, I promise)

Question 5: A little bit harder of a question. Since the first and second equation both only have y and z, we can solve it using the elimination method.

Rearrange them so that the letters are on one side and numbers on the other side.

First equation: y + 6z = -24

Second equation: z + 2y = -4

I will choose to eliminate the y (You can choose either or)

Multiply the first equation by 2

2(y + 6z = -24)

2y + 12z = -48

Now that 2y is in both equations, we can minus one equation from the other to eliminate the y (I will minus the second from the first)

First Eq: 2y + 12z = -48

Second Eq: z + 2y = -4

2y - 2y = 0y

12z - z = 11z

-48 - (-4) = -44

Type these answers into a new equation

0y + 11z = - 44

Since y is 0, ignore it. Solve for z

11z = -44

z = -44/11

z = - 4

Substitute our z into either the first or second equation and solve for y (It doesnt matter which one you choose, I just did the second equation)

z + 2y = -4

(-4) + 2y = -4

2y = -4 + 4

2y = 0

y = 0

Substitute in our y and z values into the third equation and solve for x

-6x - 6y - 6z = -12

-6x - 6(0) - 6(-4) = -12

-6x - 0 + 24 = -12

-6x = -12 - 24

-6x = -36

x = -36/-6

x = 6

6 0
3 years ago
Read 2 more answers
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