The hyperbolic cross section of a cooling tower is given by the equation 4x2 − y2 + 16y − 80 = 0. The center of the cooling towe

Question

Mice21 [21]

3 years ago

9

The hyperbolic cross section of a cooling tower is given by the equation 4x2 − y2 + 16y − 80 = 0. The center of the cooling towe

r is the same as the center of the hyperbola, and the x-axis represents the ground surface.

Mathematics

2 answers:

vlada-n [284] · Answer 1 · 2022-05-09T14:41:01+03:00

vlada-n [284]3 years ago

5 0

The attached image is the representation of the question presented. I am hoping that this answer has satisfied your query and it will be able to help you in your endeavor, and if you would like, feel free to ask another question.

bazaltina [42] · Answer 2 · 2022-05-09T16:41:28+03:00

bazaltina [42]3 years ago

3 0

I think the diameter is 6 meters and the height above ground is 8 meters both at the center