The hyperbolic cross section of a cooling tower is given by the equation 4x2 − y2 + 16y − 80 = 0. The center of the cooling towe r is the same as the center of the hyperbola, and the x-axis represents the ground surface.
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I think the diameter is 6 meters and the height above ground is 8 meters both at the center
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Answer:
x=-7
Step-by-step explanation:
-2(x+5)=4
-2x-10=4
-2x=14
2x=-14
x=-7
You add 13 and 8 it gets 21 so for X its 13
1/4+5/12=3/12+5/12=8/12=4/6=2/3
Answer:
value of x = 4
Step-by-step explanation:
here's the solution : -
=》6 - 2x = 5x - 9x + 8
shifting like terms aside,
=》6 - 8 = 5x - 9x + 2x
\_(●_●)_/
=》-2 = -2x
=》x = -2 / -2
=》x = 1
y = -0.60x - 4
because the slope stays the same because it is parallel and the y intercept for the new equation ends up being -4
