Question

The hyperbolic cross section of a cooling tower is given by the equation 4x2 − y2 + 16y − 80 = 0. The center of the cooling tower is the same as the center of the hyperbola, and the x-axis represents the ground surface.

Answer 1

The attached image is the representation of the question presented. I am hoping that this answer has satisfied your query and it will be able to help you in your endeavor, and if you would like, feel free to ask another question.

Answer 2

I think the diameter is 6 meters and the height above ground is 8 meters both at the center