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ICE Princess25 [194]
3 years ago
12

A student wants to report on the number of movies her friends watch each week. The collected data are below: 0 , 0 , 1 , 1 , 2 ,

2 , 2 , 14 Which measure of center is most appropriate for this situation and what is its value? Group of answer choices Median, 1.5 Median; 3 Mean, 1.5 Mean; 3
Mathematics
1 answer:
Nataly [62]3 years ago
4 0

Answer: median = 1.5

Step-by-step explanation:

The mean is the most common measure of center which is synonymous to average. However, the mean is affected by extreme values so it may not be the best measure of center to use in a skewed distribution.

The median is the value in the center of the data. Half of the values are less than the median and half of the values are more than the median. It is probably the best measure of center to use in a skewed distribution.

The median of

0 , 0 , 1 , 1 , 2 , 2 , 2 , 14

Median = (1+2)/2 = 1.5

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Answer:

The volume of the community swimming pool is 4 times greaters than the volume of the wading pool.

Step-by-step explanation:

By definition of rectangular prism, we get the respective formulas for the volumes of the community swimming pool and the wadling pool, respectively:

Community swimming pool

V_{c} = l\cdot w\cdot h (1)

Wading pool

V_{w} = \left(\frac{1}{2}\cdot l \right)\cdot \left(\frac{1}{2}\cdot h\right)\cdot w (2)

Where:

l – Length of the swimming pool, measured in feet.

h – Depth of the swimming pool, measured in feet.

w – Width of the swimming pool, measured in feet.

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V_{w} – Volume of the wading swimming pool, measured in cubic feet.

The ratio of the volume of the community swimming pool to the volume of the wadling pool is:

\frac{V_{c}}{V_{w}} = \frac{l\cdot w \cdot h}{\left(\frac{1}{2}\cdot l \right)\cdot \left(\frac{1}{2}\cdot h\right)\cdot w} (3)

\frac{V_{c}}{V_{w}} = \frac{1}{\frac{1}{4} }

\frac{V_{c}}{V_{w}} = 4

The volume of the community swimming pool is 4 times greaters than the volume of the wading pool.

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Step-by-step explanation:

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