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Dafna11 [192]
3 years ago
10

Please please please help me with these two problems it's urgent

Mathematics
1 answer:
eduard3 years ago
5 0
For problem #4 the answer is 100°. The triangle are congruent meaning the angles that are given both of the triangle have to have the same angles.

The triangle sum theorem is all triangles have a 180° . All the 3 angles = 180.

They gave you two angles of the triangle. So add the two angles and find the difference of 180.

50+30=80

180-80=100°

#5 set those 2 angles equal. Because the A corresponds to Q. Solve for X and plug in your x value
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An exterior angle of a triangle is equal to the sum of the two remote interior angles. True or False
Fittoniya [83]
The answer is true. Exterior Angle Theorem: The measurement of an exterior angle of a triangle is equal to the sum of the two remote interior angles. <span />
3 0
3 years ago
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Evaluate (-5z)^3 . Write your answer using only positive exponents. Evaluate any numerical powers.
Ludmilka [50]

Answer:

-125z³

Step-by-step explanation:

-5 times - 5 = 25 canceling negative

125 times -5 = -125

zXzXz = z to power of 3 =z³

7 0
3 years ago
Solve −4&gt;x÷3 i need helpppp
KonstantinChe [14]

Answer: x < -12

Step-by-step explanation:

4 0
2 years ago
On the graph shown, what is f(-1)?
Naddik [55]

Answer:

where is the graph?

Step-by-step explanation:

7 0
2 years ago
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Please help very urgent
Alik [6]

Answer:

32, <u>16</u>, <u>8</u>, <u>4</u>, <u>2</u>, 1

Explanation:

The geometric mean can be represented by \sqrt[n]{x_{1} • x_{2} • x_{3} • .. x_{n}}.

Which is the mean of the product of n numbers, used to find the average of a geometric progression.

Don't get confused by geometric mean, it is only asking you about the next numbers in the geometric sequence given the first and sixth term.

The explicit rule for a geometric sequence can be modeled by:

a_{n} = a_{1} • r^{n-1}

Where a_{n} is the nth term, a_{1} is the first term in the sequence, n is the term number, and r is the common ratio.

Since we already know the first term, a_{1} will simply be 32.

Since we know it's geometric, there will be an exponential relationship, which means that we will use the geometric mean to find the common ratio.

There are 6 total terms, r is raised to the n – 1 so 6 – 1 = 5, and that will be the degree of this root.

\sqrt[5]{\frac{a_{6}}{a_{1}}} =

\sqrt[5]{\frac{1}{32}} =

\frac{1}{2}.

Therefore: r = \frac{1}{2}.

Using all the information we have, we can find the explicit rule:

a_{n} = a_{1} • r^{n-1}

  • a_{1} = 32
  • r = \frac{1}{2}

a_{n} = a_{1} • r^{n-1} →

\boxed{a_{n} = 32 • (\frac{1}{2})^{n-1}}

________________________________

We can test that this works by substituting the number location of the term you want to find.

For instance:

a_{1} = 32 • (\frac{1}{2})^{1-1}

a_{1} = 32 • (\frac{1}{2})^{0}

a_{1} = 32 • 1

a_{1} = 32

a_{6} = 32 • (\frac{1}{2})^{6-1}

a_{6} = 32 • (\frac{1}{2})^{5}

a_{6} = 32 • \frac{1}{32}

a_{6} = 1

3 0
2 years ago
Read 2 more answers
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