Jon earns $180 per week for each sale. Write an inequality to represents how many sales he needs to make to earn at least $500.

Which of the following figures has reflectional symmetry? Help !!

aliya0001 [1]

Answer:

Figure D. (A)

When you flip the figure across like a mirror, it remains the same shape as the other side. An easy way to determine this is by cutting a line down the middle.

Reflectional symmetry states that if there exists at least one line that divides a figure into two halves such that one-half is the mirror image of the other half.

Edit: Typo!

8 0

3 years ago

How many times greater is 36 than 32?

SIZIF [17.4K]

36/32 = 1.125

36 is 1.125 times the size of 32, or 0.125 time greater than 32.

5 0

3 years ago

When y = -20, x = 4. Find y when x = 7

skelet666 [1.2K]

Answer:

y=-35

Step-by-step explanation:

The relationship between the values of x and y is multiplying by -5.

Therefore, when x equals 7, y is -35.

Just a splendiferous teen,

who listens to "Fight Song,"

stay salty...

7 0

3 years ago

Read 2 more answers

Solve x for this equation

gogolik [260]

Answer:

try c

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

A company makes a profit of $y (in thousand dollars) when it produces x computers,

leva [86]

Using quadratic function concepts, it is found that:

a) The value of a is -2000.

b) The maximum profit the company can make is of $5,000,000, when 150 computers should be produced.

c) Between 140 and 160 computers need to be produced.

The profit is modeled by:

$y = a(x - 100)(x - 200)$

Item a:

If 120 computers are produced, the profit will be $3,200,000, hence when $x = 120, y = 3200000$ , and this is used to find a.

$y = a(x - 100)(x - 200)$

$3200000 = a(120 - 100)(120 - 200)$

$-1600a = 3200000$

$a = -\frac{3200000}{1600}$

$a = -2000$

The value of a is -2000.

Item b:

We first place the quadratic function into standard form, thus:

$y = -2000(x - 100)(x - 200)$

$y = -2000(x^2 - 300x + 20000)$

$y = -2000x^2 + 600000x - 40000000$

Which has coefficients $a = -2000, b = 600000, c = -40000000$ .

Then, we have to find the vertex:

$x_V = -\frac{b}{2a} = -\frac{600000}{2(-2000)} = 150$

$\Delta = b^2 - 4ac = (600000)^2 - 4(-2000)(-40000000) = 40000000000
$

$y_V = -\frac{\Delta}{4a} = -\frac{40000000000
}{4(-2000)} = 5000000$

The maximum profit the company can make is of $5,000,000, when 150 computers should be produced.

Item c:

We are working with a concave down parabola, hence the range is between the roots of:

$y = -200x^2 + 600000x - 40000000$

$4800000 = -200x^2 + 600000x - 40000000$

$-200x^2 + 600000x - 44800000 = 0$

The coefficients are $a = -200, b = 600000, c = -44800000$ .

Then:

$\Delta = b^2 - 4ac = (600000)^2 - 4(-2000)(-44800000) = 1600000000$

$x_1 = \frac{-b - \sqrt{Delta}}{2a} = \frac{-600000 - \sqrt{1600000000}}{2(-2000)} = 160$

$x_2 = \frac{-b + \sqrt{Delta}}{2a} = \frac{-600000 + \sqrt{1600000000}}{2(-2000)} = 140$

Between 140 and 160 computers need to be produced.

A similar problem is given at brainly.com/question/24705734

8 0

3 years ago