Answer:
ind the absolute value vertex. In this case, the vertex for y=−|x|−2 is (0,−2).
(0,−2)
The domain of the expression is all real numbers except where the expression is undefined. In this case, there is no real number that makes the expression undefined.
Interval Notation:
(−∞,∞)
Set-Builder Notation: {x|x ∈ R}
For each x value, there is one y value. Select few x values from the domain. It would be more useful to select the values so that they are around the x value of the absolute value vertex.
x y
−2 −4
−1 −3
0 −2
1 −3
2 −4
Step-by-step explanation:
The given function f(x) = |x + 3| has both an absolute maximum and an absolute minimum.
What do you mean by absolute maximum and minimum ?
A function has largest possible value at an absolute maximum point, whereas its lowest possible value can be found at an absolute minimum point.
It is given that function is f(x) = |x + 3|.
We know that to check if function is absolute minimum or absolute maximum by putting the value of modulus either equal to zero or equal to or less than zero and simplify.
So , if we put |x + 3| = 0 , then :
± x + 3 = 0
±x = -3
So , we can have two values of x which are either -3 or 3.
The value 3 will be absolute maximum and -3 will be absolute minimum.
Therefore , the given function f(x) = |x + 3| has both an absolute maximum and an absolute minimum.
Learn more about absolute maximum and minimum here :
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Answer:
mean = 4
medin = violet
mode = light blue
range = 4
Step-by-step explanation:
mean = sum/no
mode = largest number
median = (n+1)/2th item
rnge = largest - smllest