Hello,
if p is false then ~p is true
if q is false then ~q is true
if ~p is true and ~q is true then <u>~q and ~p is true</u>
Check the picture below.
notice the solid circle at -4 and 3, since it includes those points.
also notice the dashed line, though the lines keeps on going those ways, is not included in the piece-wise, since it's not part fo the domain or constraints.
Answer:
B
Step-by-step explanation:
we are given a equation of a line
we want to figure out the equation of the perpendicular line passes through the <u>(</u><u>6</u><u>,</u><u>5</u><u>)</u><u> </u>points
in order to do so
recall that,

we got from our given equation that m=2
because equation of a line is y=mx+b
thus

remember that, when we want to figure out perpendicular line or parallel line we should the formula given by

since we got our perpendicular m is -½,
and
, substitute

to get the perpendicular equation you should simplify the above equation to y=mx+b form
distribute -½:

add 5 to both sides:

hence,
our answer choice is B
-(-2x-6y=-16)
2x+6y=16
4x-6y=-58
Y's cancel out, then add the rest
6x=-42
divide both sides by six
x=-7
plug x into any previous equation
2(-7)+6y=16
-14+6y=16
6y=30
y=5