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ruslelena [56]
3 years ago
6

Given one of the roots of the quadratic equation px2- 4x + 3p -8 =0 is 1 . Calculate the value of p

Mathematics
1 answer:
Natali [406]3 years ago
7 0

Answer:

Value of p is 3

Step-by-step explanation:

One of the root is 1.

So, putting 1 in the place of x in the given equation,

px²-4x+3p-8=0

or, p-4+3p-8=0

or, 4p-12=0

or, 4p=12

or, p=3

Answered by GAUTHMATH

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Find the distance between (-5,6)and (3,2).
skad [1K]

Answer:

\displaystyle d = 4\sqrt{5}

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Algebra I</u>

  • Coordinates (x, y)

<u>Algebra II</u>

  • Distance Formula: \displaystyle d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Step-by-step explanation:

<u>Step 1: Define</u>

Point (-5, 6) → x₁ = -5, y₁ = 6

Point (3, 2) → x₂ = 3, y₂ = 2

<u>Step 2: Find distance </u><em><u>d</u></em>

Simply plug in the 2 coordinates into the distance formula to find distance <em>d</em>

  1. Substitute in points [Distance Formulas]:                                                     \displaystyle d = \sqrt{(3+5)^2+(2-6)^2}
  2. [Distance] [√Radical] (Parenthesis) Add/Subtract:                                       \displaystyle d = \sqrt{(8)^2+(-4)^2}
  3. [Distance] [√Radical] Evaluate exponents:                                                    \displaystyle d = \sqrt{64+16}
  4. [Distance] [√Radical] Add:                                                                             \displaystyle d = \sqrt{80}
  5. [Distance] [√Radical] Simplify:                                                                         \displaystyle d = 4\sqrt{5}
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Hello there, this problem is just basic addition, here is what it would look like

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