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4 years ago

What specific term is used to describe the "turning on" of an enzyme ?

1 answer:

8 0

The feedback inhibitor or final product is used to describe the "turning on" of an enzyme. This happens when the final product's concentration is low, the feedback inhibitor, which is also the final product, will move out from the allosteric site in a reaction which is reversible.

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What lies between mars and Jupiter

Jlenok [28]

Answer:

B. an asteroid belt lies between them.

Explanation:

The asteroid belt is the circumstellar disc in the Solar System located roughly between the orbits of the planets Mars and Jupiter. It is occupied by numerous irregularly shaped bodies called asteroids or minor planets.

7 0

3 years ago

Name few pests which damage the crop.

adelina 88 [10]

Mostly any bug you can think of

6 0

3 years ago

What are the components of the integumentary system?

ELEN [110]

Skin, Hair, nails, and glands.

The integumentary system has the components of the
Epidermis, The epidermis is the most superficial layer of the skin that covers almost the entire body surface.

Hair.

Nails.

and the Sudoriferous Glands, Sebaceous Glands, and Ceruminous Glands.

5 0

4 years ago

Read 2 more answers

small group of 100 people decide to isolate themselves from the world and move to a small and remote deserted island. Out of thi

irina [24]

Answer:

Frequency of p $= 0.684$

Frequency of p $= 0.316$

Number of individuals with homozygous dominant (AA) $= 47$

Number of individuals with heterozygous (Aa) $= 43$

Number of individuals with homozygous recessive (aa) $= 10$

Explanation:

Out of 100 people, 10 have albino skin (aa)

So, the frequency of homozygous recessive individuals $(q^{2})$ is $\frac{10}{100} = 0.1$

Now, q will be

$= \sqrt{q^{2} } = \sqrt{0.1} \\= 0.316$

As per Hardy Weinberg's equation -

$p + q = 1$

Substituting the value of q in above equation, we get -

$p + 0.316 = 1p = 1 -0.316\\p = 0.684$

Now the frequency of homozygous dominant (AA) will be

$p^{2} = 0.684^{2} \\= 0.467$

Hence, out of 100 people $0.467 * 100 = 46.7 or 47$ people are homozygous dominant (AA)

Like wise out of 100 people $0.1 * 100 = 10$ people are homozygous recessive (aa)

As per As per Hardy Weinberg's equation-

$p^{2} + q^{2} + 2pq = 1\\$

Substituting the values in above equation, we get -

$0.467 + 0.316 + 2pq = 1\\2pq = 1 -( 0.467+ 0.1)\\2pq = 0.433$

So, out of 100 people $0.433 * 100 = 43.3 or 43$ people are heterozygous (Aa)

7 0

4 years ago

Assume that life on Earth began 3.5 billion years ago. To the nearest percent, how much of this time have anthropoids been livin

Crazy boy [7]

Answer:

Anthropoids lived for approximately 0.86% of the total time.

Explanation:

Anthropoids are the higher developed organisms that includes apes and ape mans.

The age of earth is 3500 million and anthropoids lived for about 30 million years.
By the simple calculations we can find out the data in percent which gives us the result nearest to 0.86%.
That means 0.86% of 3.5 billion year is equivalent to 30 million years (time that was lived by anthropoids).

4 0

3 years ago