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3 years ago

In 2525 hour, Matt can type 4545 page.

Mathematics

2 answers:

qaws [65]3 years ago

8 0

you round 1,8 and get 2

stiks02 [169]3 years ago

7 0

Well to get the answer you have to divide 4545 by 2525, this was you will get how many pages did he do in 1 hour... Your asnwer should be 1.8 pages

Hope this helps

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Let f(x)=3x and g(x)=x^2+5. Perform function operation g(x)/f(x). State the domain.

tangare [24]

We have that

f(x)=3x
g(x)=x²+5
g(x)/f(x)=[x²+5]/[3x]

that new function will exist for all real numbers except the value of zero, value for which it becomes indefinite

the domain is the interval (-∞,0) U (0,∞)

using a graph tool
see the attached figure

3 0

4 years ago

Could you explain how you got the answer to please

Zina [86]

Answer:

I think is 53 A

Step-by-step explanation:

6 0

3 years ago

Find the measure of the the sides of DEF then classify it by it sides. D(8,-6) E(-1,-3) F(-2,5)

Mama L [17]

Answer:

Part a) The measure of the sides of triangle DEF are

$d_D_E=\sqrt{90}\ units$

$d_E_F=\sqrt{65}\ units$

$d_D_F=\sqrt{221}\ units$

Part b) Is a scalene triangle

Step-by-step explanation:

we know that

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

we have the coordinates

D(8,-6) E(-1,-3) F(-2,5)

step 1

Find the length side DE

D(8,-6) E(-1,-3)

substitute in the formula

$d=\sqrt{(-3+6)^{2}+(-1-8)^{2}}$

$d=\sqrt{(3)^{2}+(9)^{2}}$

$d_D_E=\sqrt{90}\ units$

step 2

Find the length side EF

E(-1,-3) F(-2,5)

substitute in the formula

$d=\sqrt{(5+3)^{2}+(-2+1)^{2}}$

$d=\sqrt{(8)^{2}+(-1)^{2}}$

$d_E_F=\sqrt{65}\ units$

step 3

Find the length side DF

D(8,-6) F(-2,5)

substitute in the formula

$d=\sqrt{(5+6)^{2}+(-2-8)^{2}}$

$d=\sqrt{(11)^{2}+(-10)^{2}}$

$d_D_F=\sqrt{221}\ units$

step 4

Classify the triangle by the measure of its sides

we have

$d_D_E=\sqrt{90}\ units$

$d_E_F=\sqrt{65}\ units$

$d_D_F=\sqrt{221}\ units$

Is a scalene triangle, because is a triangle in which all three sides have different lengths.

6 0

3 years ago

There are eight students in a class. Only one of them has passed Exam P/1 and only one of them has passed Exam FM/2. No student

Svetach [21]

Answer: There is probability of 0.57 chances that exactly three students from a group of four students have not passed Exam P/1 or Exam FM/2.

Step-by-step explanation:

Total number of students = 8

Number of student who has passed Exam P/1 = 1

Number of student who has passed Exam FM/2 = 1

No student has passed more than one exam.

According to question, exactly three students from a randomly chose group of four students have not passed Exam P/1 or Exam FM/2.

So, Probability will be

$\frac{^6C_3\times ^2C_1}{^8C_4}\\\\=\frac{20\times 2}{70}\\\\=\frac{4}{7}\\\\=0.57$

Hence, there is probability of 0.57 chances that exactly three students from a group of four students have not passed Exam P/1 or Exam FM/2.

4 0

3 years ago

Two rectangles are similar. The ratio of the length of rectangle A to the length of rectangle B is 1:4. If the length of rectang

snow_lady [41]

Answer:

Hey have you tried on your own to make sure you understand it?

Step-by-step explanation:

6 0

3 years ago