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3 years ago

The manager of a grocery store selected 100 customers at random to ask what the maximum price is

Mathematics

1 answer:

Brilliant_brown [7]3 years ago

8 0

What is the rest of the question?

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Someone help me with this plss

gregori [183]

Answer:

C. b=1053

Step-by-step explanation:

Isolate b:

0.25b+168.75=432
Subtract 168, 0.25b=263.25
Divide by 0.25, b=1053

6 0

3 years ago

Read 2 more answers

Calculate 0.82 + 0.35 ?

natima [27]

ANSWER

EXPLANATION

We want to add the two numbers:

0.82 + 0.35

Using the long addition method, we have:

0 . 8 2

+ 0 . 3 5

Start on the right hand side:

4 0

2 years ago

5. Find mTOS in the figure below.

Vikentia [17]

Applying the definition of a linear pair, m∠TOS = 52°

<em>Recall:</em>

Linear pair are two angles on a straight line whose sum equals 180°.

Given:

m∠TOU = 128°
m∠SOV = (4x + 8)°

m∠TOU + m∠TOS = 180° (linear pair)

Substitute

128° + m∠TOS = 180°

Subtract 128° from both sides of the equation

m∠TOS = 180° - 128°

m∠TOS = 52°

Thus, applying the definition of linear pair, m∠TOS = 52°

Learn more about linear pair on:

brainly.com/question/3768841

7 0

2 years ago

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1. If 40% of a number is 56, what was the original number?

Setler79 [48]

Answer:

140

I am not completely sure but what i did was

56/? = 40/100

56*100

5600/40

140

7 0

3 years ago

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If the work required to stretch a spring 2 ft beyond its natural length is 6 ft-lb, how much work is needed to stretch it 6 in.

mel-nik [20]

Answer:

0.375 feet-lb

Step-by-step explanation:

We have been given that the work required to stretch a spring 2 ft beyond its natural length is 6 ft-lb. We are asked to find the work needed to stretch the spring 6 in. beyond its natural length.

We can represent our given information as:

$6=\int\limits^2_0 {F(x)} \, dx$

We will use Hooke's Law to solve our given problem.

$F(x)=kx$

Substituting this value in our integral, we will get:

$6=\int\limits^2_0 {kx} \, dx$

Using power rule, we will get:

$6=\left[ \frac{kx^2}{2} \right ]^2_0$

$6=\frac{k(2)^2}{2}-\frac{k(0)^2}{2}$

$6=\frac{4k}{2}-0\\\\k=3$

We know that 6 inches is equal to 0.5 feet.

Work needed to stretch it beyond 6 inches beyond its natural length would be $\int\limits^{0.5}_0 {kx} \, dx =\int\limits^{0.5}_0 {3x} \, dx$

Using power rule, we will get:

$\int\limits^{0.5}_0 {3x} \, dx = \left [\frac{3x^2}{2}\right]^{0.5}_0$

$\frac{3(0.5)^2}{2}-\frac{3(0)^2}{2}\Rightarrow \frac{3(0.25)}{2}-0=\frac{0.75}{2}=0.375$

Therefore, 0.375 feet-lb work is needed to stretch it 6 in. beyond its natural length.

3 0

3 years ago