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3 years ago

Factorise fully -X – 10 Pls help

Mathematics

1 answer:

Nataly_w [17]3 years ago

3 0

Answer:

-X – 10=-1(x+10) is your answer

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Given h(x) = –2 – 3, find h(-6).

igomit [66]

Answer

Step-by-step explanation:

h(-6)=-(-6)-3

h(-6)=6-3

h(-6)=3

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3 years ago

The average cost of tuition, room and board at small private liberal arts colleges is reported to be $8,500 per term, but a fina

Vlada [557]

Answer:

The test statistic for this test is 3.82.

Step-by-step explanation:

The null hypothesis is:

$H_{0} = 8500$

The alternate hypotesis is:

$H_{1} > 8500$

Our test statistic is:

$t = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$

In which X is the sample mean, $\mu$ is the value tested at the null hypothesis, $\sigma$ is the standard deviation of the population and n is the size of the sample.

In this question:

$X = 8745, \mu = 8500, \sigma = 1200, n = 350$

$t = \frac{8745 - 8500}{\frac{1200}{\sqrt{350}}} = 3.82$

The test statistic for this test is 3.82.

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4 years ago

Question 5 (1 point)

ElenaW [278]

Answer:

The volume of the shape is 560 ft^3

Step-by-step explanation:

To find the volume of the figure, we need to multiply the base area by the height of the figure

mathematically, we have the base area as a rectangular shape and its area is the product of its side lengths

We have this as 8 ft * 10 ft = 80 ft^2

So multiplying this by the height which is 7 ft, we have this as;

7 ft * 80 ft^2 = 560 ft^3

3 0

3 years ago

There are 750 spectators in the stadium of which 420 of them are woman and the rest are man what percent are men

MrMuchimi

44% of people are men

5 0

3 years ago

Read 2 more answers

Find an equation of the sphere with center (2, −10, 3) and radius 5. $$25=(x−2)2+(y−(−10))2+(z−3)2 use an equation to describe i

lana66690 [7]

In the $x,y$ plane, we have $z=0$ everywhere. So in the equation of the sphere, we have

$25=(x-2)^2+(y+10)^2+(-3)^2\implies(x-2)^2+(y+10)^2=16=4^2$

which is a circle centered at (2, -10, 0) of radius 4.

In the $x,z$ plane, we have $y=0$ , which gives

$25=(x-2)^2+10^2+(z-3)^2\implies(x-2)^2+(z-3)^2=-75$

But any squared real quantity is positive, so there is no intersection between the sphere and this plane.

In the $y,z$ plane, $x=0$ , so

$25=(-2)^2+(y+10)^2+(z-3)^2\implies(y+10)^2+(z-3)^2=21=(\sqrt{21})^2$

which is a circle centered at (0, -10, 3) of radius $\sqrt{21}$ .

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3 years ago