Ask question

Ask question

All categories

3 years ago

8

The sum of three numbers is 54. The third number is 2 times the second. The second number is 10 more than the first. What are th

e numbers?

1 answer:

Svetllana [295]3 years ago

6 0

Answer:

8, 18 and 36 respectively.

<h2>explanation</h2>

sum=54

1st number=x

2nd number=x+10

3rd number =2(x+10)=2x+20

x+x+10+2x+20=54

put the liketerms together

x+x+2x=54-10-20

4x=24

divide both sides by 4 to get

x=8

Input the other values

You might be interested in

Riley set up a snack table for her dog's birthday party. She invited all the neighborhood dogs

katen-ka-za [31]

hahaha since you don't know what i'm saying then when poop on people i will poop on you most lol

4 0

2 years ago

Aiden buys one package of 2-pound, 3-pound, and 4-pound packages of ground turkey to make turkey burgers. how many 1/3 pound tur

masha68 [24]

You need to add 2+3+4

divid into 1/3

and your answer is 0.037 longated

4 0

3 years ago

17976 / 28<br><br><br><br><br> / means divide if you didn't know :)

GREYUIT [131]

Answer:

642 you divide the two numbers

4 0

3 years ago

PLEASE ANSWER !!!

Y_Kistochka [10]

the answer is 100 milliliteres

7 0

3 years ago

Read 2 more answers

100 points.. please help?

puteri [66]

The fromula of a distance between two points:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

We have the points J(-5, 6), K(3, 4) and L(-2, 1). Substitute:

$|JK|=\sqrt{(3-(-5))^2+(4-6)^2}=\sqrt{8^2+(-2)^2}=\sqrt{64+4}=\sqrt{68}\\\\=\sqrt{4\cdot17}=\sqrt4\cdot\sqrt{17}=2\sqrt{17}\\\\|JL|=\sqrt{(-2-(-5))^2+(1-6)^2}=\sqrt{3^2+(-4)^2}=\sqrt{9+25}=\sqrt{34}\\\\|KL|=\sqrt{(-2-3)^2+(1-4)^2}=\sqrt{(-5)^2+(-3)^2}=\sqrt{25+9}=\sqrt{34}$

The perimeter of ΔJKL:

$P_{\Delta JKL}=|JK|+|JL|+|KL|\\\\P_{\Delta JKL}=2\sqrt{17}+\sqrt{34}+\sqrt{34}=2\sqrt{17}+2\sqrt{34}=2(\sqrt{17}+\sqrt{34})$

The area of ΔJKL:

$A_{\Delta JKL}=\dfrac{1}{2}|JL||KL|\\\\A_{\Delta JKL}=\dfrac{1}{2}\cdot\sqrt{34}\cdot\sqrt{34}=\dfrac{1}{2}(\sqrt{34})^2=\dfrac{1}{2}(34)=17$

4 0

3 years ago