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4 years ago

How to write polynomial with given zeros and degree and leading coefficient?

Mathematics

1 answer:

geniusboy [140]4 years ago

8 0

If the zeros are r1,r2, ..., rn and the leading coefficient is a

then
p(x)=a(x-r1)(x-r2)....(x-rn)

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Need Help on Both of these, Will give 50 Points to answerer:

vekshin1

Part A: Scatter plot with best-fit line attached. You'll find the line to have equation (approximately)

$y=51.34+3.98x$

The positive slope suggests that test scores and study time are directly are proportional.

Part B: Same as in a previous question you had posted. Pick two points on the provided line and compute the slope as best you can. For example, I might pick (2, 30) and (4, 40), which gives a slope of

$\dfrac{40-30}{4-2}=5$

and assuming the line passes through (2, 30) exactly, it would have equation

$y-2=5(x-30)\implies y=5x-148$

7 0

3 years ago

Charlie is watching hot air balloons. Balloon A has risen at a 60° angle. Balloon B has risen at an 82° angle. If the distance f

babymother [125]

Answer:

(B)1005 feet

Step-by-step explanation:

In the attached diagram

$\angle y =82^\circ\\\angle x =60^\circ$

|AG|=1400 feet

Distance from point C to point G=|CG|

Using Trigonometry in Triangle ACG

$\tan 60^\circ=\dfrac{1400}{CG}\\ CG=\dfrac{1400}{\tan 60^\circ}\\\approx 808$ feet$

Using Trigonometry in Triangle BCG'

$\tan 82^\circ=\dfrac{1400}{CG'}\\ CG'=\dfrac{1400}{\tan 82^\circ}\\\approx 197$ feet$

Therefore, the distance from balloon B from balloon A

=CG+CG'

=808+197

=1005 feet

4 0

4 years ago

Help me pls<br>this is worth 100<br>points

sergeinik [125]

Answer:

The picture is the answer.

Hope this helps!

5 0

4 years ago

Read 2 more answers

The probability that a car has a certain factory defect is 825. The probability that a car has a certain factory defect and need

ipn [44]

Answer:

90.91% probability that a car needs an oil change given that it has a certain factory defect

Step-by-step explanation:

We use the conditional probability formula to solve this question. It is

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

In which

P(B|A) is the probability of event B happening, given that A happened.

$P(A \cap B)$ is the probability of both A and B happening.

P(A) is the probability of A happening.

In this problem, we have that:

Event A: having a factory defect.

Event B: needing an oil change.

The probability that a car has a certain factory defect is 825.

So $P(A) = 0.825$

The probability that a car has a certain factory defect and needs an oil change is 750.

So $P(A \cap B) = 0.75$

What is the probability that a car needs an oil change given that it has a certain factory defect

$P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.75}{0.825} = 0.9091$

90.91% probability that a car needs an oil change given that it has a certain factory defect

5 0

4 years ago

Complete the square for the function f(x) = x² - 4x + 6. What is the minimum point on a graph of this function?

AVprozaik [17]

Answer:

2,2

Step-by-step explanation:

f(x)=(x-2)^2+2

=2,2

4 0

3 years ago