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son4ous [18]
3 years ago
7

Factor completely. n 2 + 7n - 44 (n - 4)(n - 11) (n - 4)(n + 11) (n + 4)(n - 11)

Mathematics
2 answers:
enot [183]3 years ago
4 0
The answer is (n+11)(n-4). You want to find what multiplies to make -44 and what adds to make 7.
Dovator [93]3 years ago
4 0
The answer is n = 11, 4, and -4 because factor n2 + 7n -44 and you get 11 and -4 but the rest you distribute and get n2-15n+44 and the zeros are n = 11 and 4
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Use the box plot to explain what you know about the spread of this data set.
k0ka [10]

Answer:

The Middle is 50, The outliers are 20 and 75

Step-by-step explanation:

4 0
3 years ago
In a café, I order a cup of tea and a piece of cake and it costs £1.10. The next time I order 2 cups of tea and one piece of cak
defon

Answer:

£0.50

Step-by-step explanation:

t = one cup of tea

c = one piece of cake

t + c = £1.10

2t + c = £1.70

the cost increases by £0.60 (£1.70 - £1.10) when you order one more cup of tea which means that one cup of tea costs £0.60

substitute £0.60 into t + c = £1.10

£0.60 + c = £1.10

rearrange to get c = £1.10 - £0.60 = £0.50

so one piece of cake costs £0.50

7 0
3 years ago
Read 2 more answers
The product of 12 and y increased by 11
erastovalidia [21]
Product means to multiple 12y
increase that by 11 so +11
awnser: 12y+11
3 0
3 years ago
HELP ASAP- I would give 40 points just for these 3 answers
Slav-nsk [51]
5) The relation between intensity and current appears linear for intensity of 300 or more (current = intensity/10). For intensity of 150, current is less than that linear relation would predict. This seems to support the notion that current will go to zero for zero intensity. Current might even be negative for zero intensity since the line through the points (300, 30) and (150, 10) will have a negative intercept (-10) when current is zero.

Usually, we expect no output from a power-translating device when there is no input, so we expect current = 0 when intensity = 0.


6) We have no reason to believe the linear relation will not continue to hold for values of intensity near those already shown. We expect the current to be 100 for in intensity of 1000.


8) Apparently, times were only measured for 1, 3, 6, 8, and 12 laps. The author of the graph did not want to extrapolate beyond the data collected--a reasonable choice.
7 0
3 years ago
Can someone help me with this question?
nevsk [136]

Step-by-step explanation:

1. Vertical

2. Alternate

3. congruent

4. AAS or SAA

7 0
4 years ago
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