Con la información que se encuentra a continuación completar la tabla sobre el valor posicional de los números.
1 answer:
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Answer:
1000 times
Step-by-step explanation:
Given:
The Sun is roughly 10^2 times as wide as the Earth.
The Star KW Sagittarii is roughly 10^5 times as wide as the Earth.
Question asked:
About how many times as wide as the Sun is KW Sagittarii?
Solution:
Let the width of the earth =
As the Sun is roughly 10^2 times as wide as the Earth, hence the width of the sun =
And as the Star KW Sagittarii is roughly 10^5 times as wide as the Earth, hence the width of the Star =
Now, to find that how many times width of the Star KW Sagittarii is as respect to the width of the Sun, we will simply divide:
Width of the Star KW Sagittarii =
Width of the Sun =
x canceled by x
Therefore, Star KW Sagittarii is 1000 times wider than Sun.
<em>First of all we calculated width of Sun in terms of width of earth and then calculated the width of the Star in terms of earth and for comparison we did simple division that showed that the Star KW Sagittarii is 1000 times wider than the Sun.</em>
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Answer:
Step-by-step explanation:
Given
When mass = 4kg; Acceleration = 15m/s²
Required
Determine the acceleration when mass = 10kg, provided force is constant;
Represent mass with m and acceleration with a
The question says there's an inverse variation between acceleration and mass; This is represented as thus;
Convert variation to equality
; Where F is the constant of variation (Force)
Make F the subject of formula;
When mass = 4kg; Acceleration = 15m/s²
When mass = 10kg; Substitute 60 for Force
Divide both sides by 10
<em>Hence, the acceleration is </em><em />