Answer: simple random sampling
Step-by-step explanation:
- A simple random sampling is a sampling method in which individuals are chosen randomly from the population. In this each individual has equal chances to get selected.
- If N is the population size , then for any individual , the chances for getting selected is
.
As per given , the company randomly selects 50 customers directly from the database without applying any further steps and asks them about their level of satisfaction with the company.
Thus , the sampling technique used here is simple random sampling.
Answer:
Area = 64π
Area \: = \pi {r}^{2}Area=πr
2
64 \: \pi \: = \pi {r}^{2}64π=πr
2
{r}^{2} = \dfrac{64\pi}{\pi}r
2
=
π
64π
{r}^{2} = 64r
2
=64
r \: = \: \sqrt{64} = 8r=
64
=8
Radius = 8 units
Finding the Diameter -
Diameter = Radius x 2 = 8 x 2 = 16 .
\bold{Diameter \: is \: 16 \: units}Diameteris16units
Answer:
dam this been up for a long time
Step-by-step explanation:
its just too hard sorry man
For this case we have the following function:
y = 9 (3) ^ x
Applying the following transformations we have:
Horizontal translations
Suppose that h> 0
To graph y = f (x-h), move the graph of h units to the right.
y = 9 (3) ^ (x-2)
Vertical translations
Suppose that k> 0
To graph y = f (x) -k, move the graph of k units down.
y = 9 (3) ^ (x-2) - 6
Answer:
2 units to the right
6 units down
Step-by-step explanation: The cosecant function is graphed in the given figure. we are to find the period of the function.
The period of a function is the distance travelled by the curve of the function in one complete revolution.
We can see that in the given figure, the distance between two consecutive points is given by
Therefore, the period of the cosecant function is
Thus, the correct option is (B) \pi.
