Ask question

Ask question

All categories

3 years ago

8

I tried graphing this and I messed up can someone help me graph it?

1 answer:

IrinaVladis [17]3 years ago

7 0

For x=-y+3, you add y to both sides which gives you x+y=3 then you subtract x from both sides which gives you y=-x+3.

You might be interested in

Really need help giving extra points for all the answers I need

AysviL [449]

Answer:

idek

Step-by-step explanation:

sorry

8 0

3 years ago

Log(x⁴+3x³) - log(X + 3 ) + log2 - log6 = 2logx . find the value of x

AfilCa [17]

The given equation is

$\begin{gathered} \log (x^4+3x^3)-\log (x+3)+\log 2-\log 6=2\log x \\ \log (\frac{x^4+3x^{3^{}}}{x+3})+\log \frac{2}{6}=\log x^2 \\ \log \frac{x^3(x+3)}{x+3}+\log \frac{1}{3}=\log x^2 \\ \log x^3+\log \frac{1}{3}=\log x^2 \\ \log \frac{x^3}{3}=\log x^2 \\ \frac{x^3}{3}=x^2 \\ x^3-3x^2=0 \\ x^2(x-3)=0 \end{gathered}$

hence

$x=0\text{ or x=3}$

But x cannot be zero so x=3

So the value of x is 3

h

7 0

1 year ago

A=9y+3yx solve for y

solong [7]

The answer is y= a/3(3+x)

3 0

3 years ago

Read 2 more answers

Evaluate the polynomial 6x - y for x = 3 and y =4

Mashcka [7]

6 x 3 is 18. y is equal to 4. 18 minus 4 is 14. The answer is 14.

8 0

3 years ago

Marcellus has a pitcher that contained 5/8 gallon limeade. Marcellus drank 1/4 gallon of the limeade, and Marcy drank 1/8 gallon

mash [69]

Answer:

2/5

Step-by-step explanation:

Given Marcellus drank 1/4 gallon of the limeade and Marcy drank 1/8 gallon of the limeade

Given that only 5/8 portion of the pitcher contains limeade

Total amount drunk = amount drunk by Marcellus + amount drunk by Marcy

Total amount drunk = $\frac{1}{4} +\frac{1}{8}$ = $\frac{3}{8}$

The amount of Limeade remained = The amount initially - the amount drunk

The amount remained = $\frac{5}{8} -\frac{3}{8}$ = $\frac{1}{4}$

Fractional part = amount remained / amount initially = $\frac{\frac{1}{4} }{\frac{5}{8} }$ = $\frac{2}{5}$

8 0

3 years ago