1.
Since ABCD is a rectangle, then
angleABE = 90 degrees
angle ABE + angle BEA + 41 = 180
Substitute the known and solve for angle BEA
angle BEA + 41 = 90
angle BEA = 49 degrees
But,
x + angleBEA + 61 = 180 (angles in a straight line)
x = 180 - 61 - 49
x = 70 degrees
2.
triangle XYZ is equilateral, meaning all angles in it are the same, each 60 degrees.
Therefore,
Angle YZX = 60
But Angle YZX = x + 32 (exterior angles equal to the sum of the two opposite interior angles)
60 = x + 32
Therefore,
x = 28 degrees
3.
Angle QPR = Angle QRP (equal oppo sides, equal opposite angles)
Therefore, 2angleQRP + 64 = 180 (angle sum of a triangle)
Angle QRP = 58 degrees
But angle QRP = x + 35 (exterior angles equal to the sum of the two opposite interior angles)
58 = x + 35
x = 23 degrees
B u can see it if u count it correctly
C^2=a^2+b^2
plug in; c^= 60^2+91^2
c^2=11881
find root
answer= 109cm
If u find the answer put square 2 bc its had 4 sides
Answer:
61.9
Step-by-step explanation:
Look at the number next to the tenths place which in this case is 5.
When a number is greater than or equal to 5 you round up.
So 61.85 becomes 61.9