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djverab [1.8K]
4 years ago
8

There were 60 seventh grade students who signed up for soccer tryouts last year. This year, 48 seventh graders signed up for try

outs. What is the percent decrease in the number of students from last year to this year?
Mathematics
1 answer:
Lubov Fominskaja [6]4 years ago
3 0

Answer:

20%

Step-by-step explanation:

(60 - 48) / 60 = 0.2    (20%)

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Plz help...do both plz
Gemiola [76]
The answer for number 4 is 13 and number 6 is 121 and the last problem for number 7 is 112
3 0
3 years ago
IF XPOWER 3 =27,THEN X POWER 2=
kvv77 [185]

X²= 9

X POWER 3= 27

X³= 27

The number that can be multiplied three times to get 27 is 3

Therefore X POWER 2 (X²) can be calculated as follows

= 3²

= 3 × 3

= 9

Hence XPOWER 2 is 9

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8 0
1 year ago
What is the gradient of the blue line?
anzhelika [568]

Answer:

.25 or 1/4

Step-by-step explanation:

to find gradient/ slope,

choose any two points on line and divide the difference in y- values over difference in x- values

i.e. (0, 1), (10, 3.5)

2.5/10=.25 or 1/4

4 0
3 years ago
Ms counsel scored 42 points in 3 games how many points would you expect her to make in an 11 game season
iVinArrow [24]
42 points ----> 3 games

X Points -----> 11 games

(11)(42) = 3x

462 = 3x

Divide by 3

X = 154 points
7 0
3 years ago
Often, frequency distributions are reported using unequal class widths because the frequencies of some groups would otherwise be
RUDIKE [14]

Answer:

The sample standard deviation is 13.22°F

Step-by-step explanation:

Given - Often, frequency distributions are reported using unequal

            class widths because the frequencies of some groups would

            otherwise be small or very large. Consider the following​ data,

            which represent the daytime household temperature the

            thermostat is set to when someone is home for a random sample

            of households. Determine the class​ midpoint, if​ necessary, for

             each class and approximate the mean and standard deviation

             temperature.

Temp                    Frequency                        Class Midpoint

61-64                         34                                         63

65-67                         68                                         66.5

68-69                         196                                        69

70                              191                                         70.5

71-72                         122                                         72

73-76                          81                                           75

77-80                          52                                           79

To find - The sample standard deviation is _____degrees°F.

Proof -

Temp         Frequency(f)            Midpoint(m)           m×f        ( m - 70.73 )²×f

61-64                34                            63                   2142          2031.6

65-67                68                            66.5                4522           1216.7

68-69               196                            69                  13524          586.6

70                     191                           70.5               13465.5        10.1

71-72                122                           72                   8784             196.8

73-76                  81                            75                   6075             2224.4

77-80                  52                            79                    4108            3556.4

                   ∑f = 744                                    ∑m×f = 52620.5     ∑ = 9822.6

So, Mean = \frac{52620.5}{744} = 70.73

Sample standard deviation = \frac{9822.6}{744 - 1} =  \frac{9822.6}{743} = 13.22

∴ we get

The sample standard deviation is 13.22°F

3 0
3 years ago
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