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kupik [55]
4 years ago
11

Given H (6,7) and I (-7,-6), if point G lies 1/2 of the way along segment HI, Satiago argues that point G is located at the orig

in. Is satiago correct? Justify your answer.
Mathematics
1 answer:
Lady bird [3.3K]4 years ago
3 0
Let H (6, 7) be (x₁, y₁) and I (-7, -6) be (x₂, y₂)

Mid point = [ \frac{x_1+x_2}{2},  \frac{y_1+y_2}{2}]
Mid point = [[ \frac{6+-7}{2},  \frac{7+-6}{2}]
Mid point = [ \frac{-1}{2},  \frac{1}{2}]

Santiago is not correct, the mid point is (-0.5, 0.5)
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Evaluate 3(x-1)^2 if x=4
Ronch [10]

Answer:

27

Step-by-step explanation:

3(4-1)²

3(3)²

3 x 9

= 27

5 0
4 years ago
Find the value of x which satisfies the following equation.<br> log2(x−1)+log2(x+5)=4
weqwewe [10]

\quad \huge \quad \quad \boxed{ \tt \:Answer }

\qquad \tt \rightarrow \: x = 3

____________________________________

\large \tt Solution  \: :

\qquad \tt \rightarrow \:  log_{2}(x - 1)  log_{2}(x + 5)  = 4

\qquad \tt \rightarrow \:  log_{2} \{(x - 1)(x + 5) \} = 4

[ log (x) + log (y) = log (xy) ]

\qquad \tt \rightarrow \: ( x - 1)(x + 5) =  {2}^{4}

\qquad \tt \rightarrow \:  {x}^{2}  + 5x - x - 5 =  16

\qquad \tt \rightarrow \:  {x}^{2}  + 4x - 5 - 16 = 0

\qquad \tt \rightarrow \:  {x}^{2}  + 4x -21 = 0

\qquad \tt \rightarrow \:  {x}^{2}  + 7x - 3x - 21 = 0

\qquad \tt \rightarrow \:  x(x + 7) - 3(x + 7) = 0

\qquad \tt \rightarrow \: (x + 7)(x - 3) = 0

\qquad \tt \rightarrow \: x =  - 7 \:  \: or \:  \: x = 3

The only possible value of x is 3, since we can't operate logarithm with a negative integer in it.

\qquad \tt \rightarrow \: x = 3

Answered by : ❝ AǫᴜᴀWɪᴢ ❞

4 0
2 years ago
30 POINTS HELPPPPPP
riadik2000 [5.3K]

Answer:

$20.40

Step-by-step explanation:

4 0
3 years ago
Cyclist A leaves point X at 12 noon and travels at constant velocity in a straight path. Cyclist B leaves point X at 2 p.m. trav
fredd [130]

Answer:

37.5 miles per hour

Step-by-step explanation:

The question might be trying to confuse the reader. Point (1) which states the difference in weight does not show any evidence on how it affects the speed of both cyclist. Point (2) show an important point where the distance traveled is 75 miles.

Cyclist B, who leave point X at 2pm overtook cyclist A at 4pm, showing that the time it took for B to overtook A is 2 hours

Speed = distance / time

= 75 miles / 2 hours

= 37.5 miles per hour

5 0
3 years ago
Given right triangle jkl, what is the value of cos(l)?
miss Akunina [59]
Taking K as the right angle =>

cos (L) = segment LK / hypotenuse

=> cos(L) = segment LK / √ [ (segment LK)^2 + (segment KJ)^2 ]
7 0
4 years ago
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