A=-2;b=9;c=9;
delta=b^2-4*a*c
root1=(-b+(delta^(0.5)))/(2*a)
<span>root2=(-b-(delta^(0.5)))/(2*a)
delta =153
root1 = -0.8423
root2 =<span> 5.3423
Correct Answer is D</span></span>
Answer:
y=2x-2
Step-by-step explanation:
y=mx+b is point slope form.
let m= the slope
b=y intercept
the y intercept is -2
y=mx-2
then after finding the slope (2) put that in
y=2x-2
Using vector concepts, it is found that:
The component form is of approximately (-9.58, 7,22). It means that the ship is about 9.58 miles to the west and about 7.22 miles to the north of where the ship left the port.
<h3>How can a vector be represented in component notation?</h3>
Given a magnitude M and angle
, then a vector V can be represented as follows in component notation:

In this problem, the magnitude and the angle are given, respectively, by:

Hence:
V = [12cos(143º), 12sin(143º)] = (-9.58, 7,22).
Which means a displacement of 9.58 miles to the west(negative x = west) and 7.22 miles to the north(positive y = north).
The component form is of approximately (-9.58, 7,22). It means that the ship is about 9.58 miles to the west and about 7.22 miles to the north of where the ship left the port.
More can be learned about vectors at brainly.com/question/24606590
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H(-2)=(-2)/2
h(-2)=-2
hope this helps!!!
Answer:
X= 18; Y=15
Step-by-step explanation:
As a student myself working this out I cannot explain how I got the answer but I know it is correct.