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cricket20 [7]
3 years ago
7

I need the answer i don't know the answer so please help me

Mathematics
1 answer:
Alekssandra [29.7K]3 years ago
5 0
1200 - 450 = 750 liters that he needs to fill up

81.5 x 750 = €61,125 
€61,125 x 0.075 = €4,584.38 (discount as a loyal customer)
total paid with discount = €61,125 - €4,584.38 = €56,540.62

answer
Mr. Leonard gets  €4,584.38 discount on his purchase
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365x + 125 = 250x + 175
maxonik [38]
First, set up the equation. 
365x + 125 = 250x + 175 

Second, combine like terms on the same side by subtracting 250x and 125 from both sides.

365x +125 = 250x + 175  
-250x  -125   -250x -125 
__________________
115x = 50

Third, divide both sides by 115 to solve for x.

115x = 50
----      ----
115     115 

Fourth, simplify. 

x=50/115=10/23 or 0.435

7 0
3 years ago
What’s the answer for this equation?<br><br> 1/2 * (1, 341 + 625)
Marysya12 [62]

Answer:

1,966 I think

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
What is the integer of-2​
Gnom [1K]

Answer:

-2

Step-by-step explanation:

The integer of - 2 is - 2 only as integers can be positive and negative whole numbers

4 0
3 years ago
Help me please I need it
7nadin3 [17]

Answer:

A

Step-by-step explanation:

The formula for a rectangular prism is length*width*height. Thus, the equation would be 6*4*16, which equals 384 cm^3.

6 0
2 years ago
Does anybody know how to do time with exponential decay
My name is Ann [436]
<span>From the message you sent me:

when you breathe normally, about 12 % of the air of your lungs is replaced with each breath. how much of the original 500 ml remains after 50 breaths

If you think of number of breaths that you take as a time measurement, you can model the amount of air from the first breath you take left in your lungs with the recursive function

b_n=0.12\times b_{n-1}

Why does this work? Initially, you start with 500 mL of air that you breathe in, so b_1=500\text{ mL}. After the second breath, you have 12% of the original air left in your lungs, or b_2=0.12\timesb_1=0.12\times500=60\text{ mL}. After the third breath, you have b_3=0.12\timesb_2=0.12\times60=7.2\text{ mL}, and so on.

You can find the amount of original air left in your lungs after n breaths by solving for b_n explicitly. This isn't too hard:

b_n=0.12b_{n-1}=0.12(0.12b_{n-2})=0.12^2b_{n-2}=0.12(0.12b_{n-3})=0.12^3b_{n-3}=\cdots

and so on. The pattern is such that you arrive at

b_n=0.12^{n-1}b_1

and so the amount of air remaining after 50 breaths is

b_{50}=0.12^{50-1}b_1=0.12^{49}\times500\approx3.7918\times10^{-43}

which is a very small number close to zero.</span>
5 0
3 years ago
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