Answer:
I think it's {3, 6, 12, 18}
Step-by-step explanation:
Domain: all x-values that are to be used (independent values).
Answer:
4 miles
Step-by-step explanation:
Lets solve the question,
Given dimensions are:
Length = 26 feet
Width = 14 feet
concrete walkway with width = c
After installing the concrete walkway dimensions of the walkway will be,
Length = 26 + 2c
Width = 14 + 2c
She wants to build a wooden deck around the pool with a concrete walkway of width = w
Thus the dimensions of the wooden deck around the pool will be,
Length = 
Width = 
Now the perimeter of the wooden deck will be,
Perimeter = 2(length + width)
![= 2[(26 +2c + 2w) + 2(14 + 2c + 2w)] = 2(40 + 4c + 4w) = (80 + 8c + 8w)](https://tex.z-dn.net/?f=%3D%202%5B%2826%20%2B2c%20%2B%202w%29%20%2B%202%2814%20%2B%202c%20%2B%202w%29%5D%20%20%20%20%20%20%20%20%20%20%20%20%20%20%20%20%3D%202%2840%20%2B%204c%20%2B%204w%29%20%20%20%20%20%20%20%20%20%20%20%20%20%20%20%20%3D%20%2880%20%2B%208c%20%2B%208w%29)
Therefore, perimeter of the wooden deck would be: 80 + 8c + 8w
Perimeter = (80 + 8c + 8w)
Learn more about Perimeter on:
brainly.com/question/397857
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Triangle inequality rule states that the sum of eachpair of sides must be greater than the third sides.
240 + 123 > 207 true
240 + 207 > 123 true
123 + 207 > 240 true
A = √(s(s-a)(s-b)(s-c))
s is the semi-perimeter (a + b + c)/2
s = (240 + 123 + 207)/2
s = 285
A = √(285*(285-249)(285-123)(285-207))
A = 12,730 units^2
Answer:
Step-by-step explanation:
9) PQR Is an isosceles triangle
=> ∠PRQ = (180° - x)/2
PRS is an isosceles right triangle
=> ∠PRS = 45°
Have: ∠PRS + ∠PRQ = 115°
=> 
=> 180 - x = (115 - 45).2 = 140
<=> x = 180 - 140 = 40
10) ABD is an isosceles right triangle => ∠ABD = 45°
BCD is an equilateral triangle => ∠CBD = 60°
have: x = ∠ABD + ∠CBD = 45° + 60° = 105°
11) have: x = y (2)
PQT is an isosceles triangle => ∠PQT = 180 - 70.2 = 40
QTS is an isosceles triangle => ∠TQS = 180 -2x
QRS is an isosceles triangle => ∠RSQ = y
have: 40 + 180 - 2x + y = 180 => 2x - y = 40 (1)
(1)(2) => 
=> x + y = 80
12) EFJ Is an equilateral triangle => ∠FJE = 60
∠FJE is the outer angle of the triangle FHJ but FHJ is an isosceles triangle
=> 60 = 2.∠JHF => ∠JHF = 30°
∠JHF is the outer angle of the triangle FHG
=> 30° = 2x
<=> x = 15°