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igor_vitrenko [27]
3 years ago
12

What is "h"? h+1/2=3 1/4

Mathematics
1 answer:
yarga [219]3 years ago
6 0
For this equation
H+1/2= 3 1/4

H is a variable, so it must have a value to it. So it would be 2.75+1/2= 3 1/4
Or 3 1/4 / 1/2 = 2.75

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State the domain plssssa
Elza [17]

Answer:

I think it's {3, 6, 12, 18}

Step-by-step explanation:

Domain: all x-values that are to be used (independent values).

7 0
3 years ago
If Jay ran 1 mile in 10 minutes on Monday, 2 miles in 20 minutes on Tuesday,
earnstyle [38]

Answer:

4 miles

Step-by-step explanation:

5 0
3 years ago
Carlita has a swimming pool in her backyard that is rectangular with a length of 26 feet and a width of 14 feet. She wants to in
meriva

Lets solve the question,

Given dimensions are:

Length = 26 feet

Width = 14 feet

concrete walkway with width = c

After installing the concrete walkway dimensions of the walkway will be,

Length = 26 + 2c

Width = 14 + 2c

She wants to build a wooden deck around the pool with a concrete walkway of width = w

Thus the dimensions of the wooden deck around the pool will be,

Length = 26 + 2c + 2w

Width = 14 + 2c + 2w

Now the perimeter of the wooden deck will be,

Perimeter = 2(length + width)

 = 2[(26 +2c + 2w) + 2(14 + 2c + 2w)]                = 2(40 + 4c + 4w)                = (80 + 8c + 8w)

Therefore, perimeter of the wooden deck would be: 80 + 8c + 8w

Perimeter = (80 + 8c + 8w)

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brainly.com/question/397857

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6 0
1 year ago
Determine whether a triangle can be formed with the given side lengths. If so, use Heron's formula to find the area of the trian
kipiarov [429]
Triangle inequality rule states that the sum of eachpair of sides must be greater than the third sides.
 240 + 123 > 207 true
240 + 207 > 123 true
123 + 207 > 240 true

A = √(s(s-a)(s-b)(s-c))
s is the semi-perimeter (a + b + c)/2
s = (240 + 123 + 207)/2
s = 285
A = √(285*(285-249)(285-123)(285-207))
A = 12,730 units^2
4 0
3 years ago
I NEED HELP !!! 30 points!!!! and brainliest :)<br><br>please give sensible answer :(<br><br><br>​
Allushta [10]

Answer:

Step-by-step explanation:

9) PQR Is an isosceles triangle

=> ∠PRQ = (180° - x)/2

PRS is an isosceles right triangle

=> ∠PRS = 45°

Have: ∠PRS + ∠PRQ = 115°

=> \frac{180-x}{2}+45=115 \\

=> 180 - x = (115 - 45).2 = 140

<=> x = 180 - 140 = 40

10) ABD is an isosceles right triangle => ∠ABD = 45°

BCD is an equilateral triangle => ∠CBD = 60°

have: x = ∠ABD + ∠CBD = 45° + 60° = 105°

11) have: x = y (2)

PQT is an isosceles triangle => ∠PQT = 180 - 70.2 = 40

QTS   is an isosceles triangle => ∠TQS = 180 -2x

QRS   is an isosceles triangle => ∠RSQ = y

have: 40 + 180 - 2x + y = 180 => 2x - y = 40 (1)

(1)(2) => \left \{ {{y=x} \atop {2x-y=40}} \right.\\\\=> \left \{ {{x=40} \atop {y=40}} \right.

=> x + y = 80

12) EFJ Is an equilateral  triangle => ∠FJE = 60

∠FJE is the outer angle of the triangle FHJ but FHJ is an isosceles triangle

=> 60 = 2.∠JHF => ∠JHF = 30°

∠JHF is the outer angle of the triangle FHG

=> 30° = 2x

<=> x = 15°

7 0
2 years ago
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