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spayn [35]
3 years ago
13

Fruit juice makes up 2/3 of the liquid ingredients in Alonzo's punch recipe. Estimate how many gallons of fruit juice are needed

to make 8 1/2 gallons of punch.
Mathematics
1 answer:
antiseptic1488 [7]3 years ago
6 0
2 and 2/3 gallons of fruit juice is needed
You might be interested in
I will give brainiest to whoever answers correctly !!
tigry1 [53]

Answer:

The graduate will have $4,084.97 when he cashes in the CD at the end of the 36-months.

Step-by-step explanation:

This can be determined using the formula for calculating the future value (FV) formula as follows:

FV = PV * (1 + r)^n ................................. (1)

Where;

FV = Future value or the amount the graduate will have at end of 36 months = ?

PV = Present value or the total amount invested = Cash gifts from friends and relatives + Amount of 3 scholarships he received = $900 + $250 + $300 + $1,400 = $2,850

r = daily interest rate = 1% / 360 = 0.01 / 360 = 0.0000277777777777778

n = number of days = 36 months * 360 days = 12,960

Substituting the values into equation (1), we have:

FV = $2,850 * (1 + 0.0000277777777777778)^12,960

FV = $2,850 * 1.43332224806396

FV = $4,084.96840698229

Approximating to the nearest cent as required, we have:

FV = $4,084.97

Therefore, the graduate will have $4,084.97 when he cashes in the CD at the end of the 36-months.

5 0
2 years ago
A boy is standing next to a radio. As he moves away from the radio, which would MOST LIKELY occur?
Alexxandr [17]
The last one im pretty sure
5 0
3 years ago
Read 2 more answers
Will mark brainliest for the correct answer!
romanna [79]

Part (a)

Focus on triangle PSQ. We have

angle P = 52

side PQ = 6.8

side SQ = 5.4

Use of the law of sines to determine angle S

sin(S)/PQ = sin(P)/SQ

sin(S)/(6.8) = sin(52)/(5.4)

sin(S) = 6.8*sin(52)/(5.4)

sin(S) = 0.99230983787513

S = arcsin(0.99230983787513)

S = 82.889762826274

Which is approximate

------------

Use this to find angle Q. Again we're only focusing on triangle PSQ.

P+S+Q = 180

Q = 180-P-S

Q = 180-52-82.889762826274

Q = 45.110237173726

Which is also approximate.

A more specific name for this angle is angle PQS, which will be useful later in part (b).

------------

Now find the area of triangle PSQ

area of triangle = 0.5*(side1)*(side2)*sin(included angle)

area of triangle PSQ = 0.5*(PQ)*(SQ)*sin(angle Q)

area of triangle PSQ = 0.5*(6.8)*(5.4)*sin(45.110237173726)

area of triangle PSQ = 13.0074347717966

------------

Next we'll use the fact that RS:SP is 2:1.

This means RS is twice as long as SP. Consequently, this means the area of triangle RSQ is twice that of the area of triangle PSQ. It might help to rotate the diagram so that line PSR is horizontal and Q is above this horizontal line.

We found

area of triangle PSQ = 13.0074347717966

So,

area of triangle RSQ = 2*(area of triangle PSQ)

area of triangle RSQ = 2*13.0074347717966

area of triangle RSQ = 26.0148695435932

------------

We're onto the last step. Add up the smaller triangular areas we found

area of triangle PQR = (area of triangle PSQ)+(area of triangle RSQ)

area of triangle PQR = (13.0074347717966)+(26.0148695435932)

area of triangle PQR = 39.0223043153899

------------

<h3>Answer: 39.0223043153899</h3>

This value is approximate. Round however you need to.

===========================================

Part (b)

Focus on triangle PSQ. Let's find the length of PS.

We'll use the value of angle Q to determine this length.

We'll use the law of sines

sin(Q)/(PS) = sin(P)/(SQ)

sin(45.110237173726)/(PS) = sin(52)/(5.4)

5.4*sin(45.110237173726) = PS*sin(52)

PS = 5.4*sin(45.110237173726)/sin(52)

PS = 4.8549034284642

Because RS is twice as long as PS, we know that

RS = 2*PS = 2*4.8549034284642 = 9.7098068569284

So,

PR = RS+PS

PR = 9.7098068569284 + 4.8549034284642

PR = 14.5647102853927

-------------

Next we use the law of cosines to find RQ

Focus on triangle PQR

c^2 = a^2 + b^2 - 2ab*cos(C)

(RQ)^2 = (PR)^2 + (PQ)^2 - 2(PR)*(PQ)*cos(P)

(RQ)^2 = (14.5647102853927)^2 + (6.8)^2 - 2(14.5647102853927)*(6.8)*cos(52)

(RQ)^2 = 136.420523798282

RQ = sqrt(136.420523798282)

RQ = 11.6799196828694

--------------

We'll use the law of sines to find angle R of triangle PQR

sin(R)/PQ = sin(P)/RQ

sin(R)/6.8 = sin(52)/11.6799196828694

sin(R) = 6.8*sin(52)/11.6799196828694

sin(R) = 0.4587765387107

R = arcsin(0.4587765387107)

R = 27.3081879220073

--------------

This leads to

P+Q+R = 180

Q = 180-P-R

Q = 180-52-27.3081879220073

Q = 100.691812077992

This is the measure of angle PQR

subtract off angle PQS found back in part (a)

angle SQR = (anglePQR) - (anglePQS)

angle SQR = (100.691812077992) - (45.110237173726)

angle SQR = 55.581574904266

--------------

<h3>Answer: 55.581574904266</h3>

This value is approximate. Round however you need to.

8 0
3 years ago
Please show work
cluponka [151]

Answer:

34.2 m

Step-by-step explanation:

We know that

Area of parallelogram = Base × Height

690.84 = B × 20.2

690.84/20.2 = B

34.2 = B

Hence,

Base of parallelogram is 34.2 m

5 0
2 years ago
Read 2 more answers
What is the simplified form of √10000x^64 ? 5000x^32 5000x^8 100x^8 100x^32
denis23 [38]

Answer:

Option (d) is correct.

\sqrt{10000x^{64}}=100x^{32}

Step-by-step explanation:

Given : Expression \sqrt{10000x^{64}}

We have to write a simplified form of the given expression \sqrt{10000x^{64}}

Consider the given expression \sqrt{10000x^{64}}

\mathrm{Apply\:radical\:rule\:}\sqrt[n]{ab}=\sqrt[n]{a}\sqrt[n]{b},\:\quad \mathrm{\:assuming\:}a\ge 0,\:b\ge 0

=\sqrt{10000}\sqrt{x^{64}}

Factor 10000 as 10000=100^2

\mathrm{Apply\:radical\:rule}:\quad \sqrt[n]{a^n}=a

\sqrt{100^2}=100

also, \mathrm{Apply\:radical\:rule\:}\sqrt[n]{a^m}=a^{\frac{m}{n}},\:\quad \mathrm{\:assuming\:}a\ge 0

We have,

\sqrt{x^{64}}=x^{\frac{64}{2}}=x^{32}

Thus, \sqrt{10000x^{64}}=100x^{32}

8 0
3 years ago
Read 2 more answers
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