A trampoline has a rectangular jumping surface that is 10.3 feet long and 9.3 feet wide . What is the area of the jumping surfac
1 answer:
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Answer:
sqrt(98) aka
Step-by-step explanation:
To find the third side we need to use the Pythagorean theorem (a^2 + b^2 = c^2) so let 3 = a and b = sqrt(89) so a^2 = 9 and for b^2 just ignore the square root so b^2 = 89 then we add 9 and 89 89 + 9 = 98 so c^2 = 98 then we do the square root of 98 since the square root of 98 isn't a whole number/ has a decimal we just leave it written as sqrt(98)