Answer:
10.1 years.
Step-by-step explanation:
It is given that,
Principal = 9000
Rate of interest = 5%
No. of times interest compounded = 2 times in an year
Amount after certain time = 14800
The formula for amount:
where, P is principal, r is rate of interest, n is no. of times interest compounded in an year and t is time in years.
Substitute the given values in the above formula.
Taking log both sides.
![[\because \log a^b=b\log a]](https://tex.z-dn.net/?f=%5B%5Cbecause%20%5Clog%20a%5Eb%3Db%5Clog%20a%5D)
Therefore, the required time is 10.1 years.
If they saved £29 all together, and if each of them saved the same amount,
then each saved £29/4 = £7.25 or £7 and 25p.
(Before decimalization in 1971, £7.25 would have been £7 and 5s .)
See picture for solution to your problem.
Answer:
(53.3; 56.1)
Step-by-step explanation:
Given that:
Sample size, n = 41
Mean, xbar = 54.7
Standard deviation, s = 5.3
Confidence level, Zcritical at 90% = 1.645
Confidence interval :
Xbar ± Margin of error
Margin of Error = Zcritical * s/sqrt(n)
Margin of Error = 1.645 * 5.3/sqrt(41)
Margin of Error = 1.362
Lower boundary = 54.7 - 1.362 = 53.338
Upper boundary = 54.7 + 1.362 = 56.062
(53.3 ; 56.1)
