Answer:
No
Step-by-step explanation:
An extraneous solution is a root of a transformed equation which is not a root of the original equation because it was not included in the domain of the original equation.
Ahmed is solving ![2\sqrt[3]{x-7}+11=3](https://tex.z-dn.net/?f=2%5Csqrt%5B3%5D%7Bx-7%7D%2B11%3D3)
for x.
His steps were:
![\begin{aligned}2\sqrt[3]{x-7}&=-8\\ \sqrt[3]{x-7}&=-4\\ \left(\sqrt[3]{x-7}\right)^3&=(-4)^3\\ x-7&=-64 \end{aligned}](https://tex.z-dn.net/?f=%5Cbegin%7Baligned%7D2%5Csqrt%5B3%5D%7Bx-7%7D%26%3D-8%5C%5C%20%20%5Csqrt%5B3%5D%7Bx-7%7D%26%3D-4%5C%5C%20%20%5Cleft%28%5Csqrt%5B3%5D%7Bx-7%7D%5Cright%29%5E3%26%3D%28-4%29%5E3%5C%5C%20%20x-7%26%3D-64%20%5Cend%7Baligned%7D)
Since cube roots <u>do not give two solutions when solved</u>, it is <u>not necessary </u>to check his answers for extraneous solutions.
A numerical factor<span> of a </span>term<span> is any number that can be factored out of the coefficient.</span>
4 - -2
,...........................
Answer:
x = -6/5
y =7/5
Step-by-step explanation:
2x + y = - 1
x - 2y = - 4
Multiply the first equation by 2 so we can eliminate y
2(2x + y = - 1)
4x + 2y = -2
Add this to the second equation
4x + 2y = -2
x - 2y = - 4
---------------------
5x + 0y = -6
Divide by 5
5x/5 = -6/5
x = -6/5
Multiply the second equation by -2 so we can eliminate x
-2(x - 2y = - 4)
-2x+4y = 8
Add this to the first equation
2x + y = - 1
-2x+4y = 8
---------------------
0x + 5y = 7
Divide by 5
5y/5 = 7/5
y =7/5
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