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melomori [17]
3 years ago
5

A teacher surveys a sample of students from Lake Middle School. He asks the students where they’d like to go for a field trip. H

e records these results: 80 choose the aquarium. 60 choose the science center. 30 choose the planetarium. 40 choose the farm. The teacher wants to figure out the relative frequency of a student choosing the aquarium. He will then estimate how many students out of all 1000 at the school are likely to choose the aquarium. Answer the questions to solve the problem. 1. How many students did the teacher survey? Write your answer in the space below. 2. What is the relative frequency of a student choosing the aquarium? Give your answer as a decimal rounded to the nearest hundredth. Show your work. Write your answer in the space below. 3. Suppose the teacher surveys one student at random. Based on the survey results, what is the estimated probability that the student chooses the aquarium? Write your answer in the space below. 4) Write and solve a proportion that the teacher can use to estimate how many students in the whole school would choose the aquarium. Show your work. Write your answer in the space below.
Mathematics
1 answer:
monitta3 years ago
6 0

Answer:

https://brainly.in/question/30560329

Step-by-step explanation:

Those are the answers I found on brainly

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Use the information to complete the task.
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3 years ago
Some transportation experts claim that it is the variability of speeds, rather than the level of speeds, that is a critical fact
scZoUnD [109]

Answer:

Explained below.

Step-by-step explanation:

The claim made by an expert is that driving conditions are dangerous if the variance of speeds exceeds 75 (mph)².

(1)

The hypothesis for both the test can be defined as:

<em>H</em>₀: The variance of speeds does not exceeds 75 (mph)², i.e. <em>σ</em>² ≤ 75.

<em>Hₐ</em>: The variance of speeds exceeds 75 (mph)², i.e. <em>σ</em>² > 75.

(2)

A Chi-square test will be used to perform the test.

The significance level of the test is, <em>α</em> = 0.05.

The degrees of freedom of the test is,

df = n - 1 = 55 - 1 = 54

Compute the critical value as follows:

\chi^{2}_{\alpha, (n-1)}=\chi^{2}_{0.05, 54}=72.153

Decision rule:

If the test statistic value is more than the critical value then the null hypothesis will be rejected and vice-versa.

(3)

Compute the test statistic as follows:

\chi^{2}=\frac{(n-1)\times s^{2}}{\sigma^{2}}

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The test statistic value is, 68.184.

Decision:

cal.\chi^{2}=68.184

The null hypothesis will not be rejected at 5% level of significance.

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7 0
3 years ago
Jason wants to add a fence to his yard to make it the shape of a rectangle. What is the measure of angle MKJ in the portion of t
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Answer:

\angle MKJ  = 34

Step-by-step explanation:

Given

\angle LKJ = 124

Required

Find \angle MKJ

From the attachment:

The measure of \angle MKJ is calculated using the following expression:

\angle MKJ  + \angle LKM = \angle LKJ

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The expression becomes

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\angle MKJ  = 124 - 90

\angle MKJ  = 34

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2 years ago
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