Answer:
Option D. 3.73
Step-by-step explanation:
we know that

and

step 1
Find cos(X)
we have

we know that

substitute




step 2
Find tan(x)

substitute

step 3
Find sin(y)
we have

we know that

substitute




step 4
Find tan(y)

substitute

step 5
Find tan(x+y)

substitute
![tan(x+y)=[1/\sqrt{3}+1}]/[{1-1/\sqrt{3}}]=3.73](https://tex.z-dn.net/?f=tan%28x%2By%29%3D%5B1%2F%5Csqrt%7B3%7D%2B1%7D%5D%2F%5B%7B1-1%2F%5Csqrt%7B3%7D%7D%5D%3D3.73)
X = 8.5 because 8.5 x 2 = 17 and 17 + 1 = 18
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➷ Simply substitute the values into the equations to see if it's correct:
Since the time taken will be more than 2 hours, we can try it with the value 3
t(x) = 70 + 5(3) = 85
g(x) = 30 + 15(3) = 75
As you can see, this is the incorrect choice as when a value more than 2 hours is used, the second engineer has a cheaper cost.
➶ Hope This Helps You!
➶ Good Luck (:
➶ Have A Great Day ^-^
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