Answer:
b=9
Step-by-step explanation:
divide by 3 on both sides to get the variable (b) by itself
Answer:
probability of a crash with at least one fatality if a driver drives while legally intoxicated (BAC greater than 0.09) = 0.001932
Step-by-step explanation:
P(BAC=0|Crash with fatality)=0.625
P(BAC is between .01 and .09|Crash with fatality)=0.302
P(BAC is greater than .09|Crash with fatality)=0.069
Let the event of BAC = 0 be X
Let the event of BAC between 0.01 and 0.09 be Y
Let the event of BAC greater than 0.09 be Z
Let the event of a crash with at least one fatality = C
P(X|C) = 0.625
P(Y|C) = 0.302
P(Z|C) = 0.069
P(C) = 0.028
probability of a crash with at least one fatality if a driver drives while legally intoxicated (BAC greater than 0.09) = P(C n Z)
But note that the conditional probability of probability that a driver is intoxicated (BAC greater than 0.09) given that there was a crash that involved at least a fatality is given by
P(Z|C) = P(Z n C)/P(C)
P(Z n C) = P(Z|C) × P(C) = 0.069 × 0.028 = 0.001932
Hope this Helps!!!
Answer: 7b^(4)c^(3)+3b^(3)c^(4)
Step-by-step explanation: hope this helps have a nice day :)
F(t)
= t2 + 4t − 14
y + 14 + 4 = (
t2 + 4t +4)
y + 18 = ( t +
2)^2
so the vertex
of the parabola is ( -2 , -18)
<span>the axis of
symmetry is y = -18</span>
The answer would definitely be between June-November, because the US is where my aunt lives, and she nearly died! :0
