Answer:
<h3>The answer is 0.002 g/cm³</h3>
Explanation:
The density of a substance can be found by using the formula
From the question
mass of sphere = 4000 g
Volume of a sphere is given by
where r is the radius
From the question
diameter = 150 cm
The volume of the sphere is
We have the answer as
volume = 1767145.86 cm³
So we have
We have the final answer as
<h3>0.002 g/cm³</h3>
Hope this helps you
Answer:The main difference between vascular and non-vascular plants is that a vascular plant has vascular vessels to carry water and food to all the different parts of the plant. ... Non vascular plants are most commonly found in moist environments, which ensures they get enough water without relying on roots.
Explanation:
Answer:
Partial pressure of ICl at equilibrium is 1.69 atm
Partial pressure of chloride gas at equilibrium is 0.00631 atm.
Partial pressure of iodine gas at equilibrium is 0.00631 atm.
Explanation:
The partial pressure of ICl initially = 1.70 atm
The equilibrium constant of the reaction =
Initially
1.70 atm 0 0
At equilibrium
(1.70-2p) p p
The expression of equilibrium constant is given by :
Solving for p :
p = 0.00631 atm
Partial pressure of ICl at equilibrium = 1.70 atm- 2 0.00631 atm = 1.69 atm
Partial pressure of chloride gas at equilibrium = 0.00631 atm.
Partial pressure of iodine gas at equilibrium = 0.00631 atm.
Answer:
It will take 0.0205s for 79% of cyclobutane to decompose
Explanation:
Step 1: Data given
Temperature = 1000 °C
Reaction is first order
rate constant = 76*1/s
The initial cyclobutane concentration is 1.63M
How long (in seconds) will it take for 79% of the cyclobutane to decompose?
When 79% decomposes, there will remain 21 %
ln ([A]0 / [A]t) * = k*t
There are four variables in the rate law, so if we know three of them, we can determine the fourth. In this case we know [A]0, [A], and k, and need to find t.
⇒ with [A]0 = the original amount = 100 % =1
⇒ with [A]t = the amount after it's decomposed = 21 % =0.21
⇒ k = the rate constant = 76/s
⇒ t= the time needed = ?
ln (100/21) = 76t
t = 0.0205 s
It will take 0.0205s for 79% of cyclobutane to decompose