The volume of the sample after the reaction : V₂=5.484 L
<h3>Further explanation</h3>
Given
Reaction
2HBr(g) + Cl2(g) => 2HCl (g)+Br2(g)
0.1100 mol of HBr(g)
5x10⁻² mol of Cl2(g)
Required
The volume of the sample after reaction
Solution
Find limiting reactant :
0.11/2 : 0.05/1 = 0.055 : 0.05
Limiting reactant : Cl₂
mol Products based on mol Cl₂
mol products = mol HCl + mol Br₂
mol products = 2/1x0.05 + 1/1x0.05
mol products = 3 x 0.05 = 0.15
mol reactants = 0.11 + 0.05 = 0.16
<em>From Avogadro's law, </em>
In the same T, P, and V, the gas contains the same number of molecules
So the ratio of gas volume will be equal to the ratio of gas moles
V₁/n₁=V₂/n₂
1 = reactants, 2 = products
Input the value :
5.85/0.16=V₂/0.15
V₂=5.484 L
