The answer to your question would be a cone
Answer:
From the given data, the typical appropriation is utilized rather than t distribution for testing. The thicknesses of the curve similarly influence both normal distribution and territory of t distribution. The normal distribution test and t test give a similar dismissal for the invalid theory for any tail of the test. Besides, the tests normal sampling distribution and t sampling distribution give a similar dismissal to null hypothesis.
Along these lines, the outcomes got by utilizing normal distribution and t distribution are distinguished as same and for each situation, the tail thickness doesn't influence the event of the basic qualities.
The trick here is to relate the NUMBER of coins to each other in one equation, and then the VALUE of the coins in another equation. If I have 1 dime, that 1 dime is worth 10 cents. The number of dimes is obviously not equal to the value. Let's call quarters q and dimes d. The number of these 2 types of coins added together is 80 coins. So q + d = 80. Now, we know that quarters are worth .25 and dimes are worth .1, so we express a quarter's worth as .25q; we express a dime's worth as .1d. The value of the coins we have is 14.90. So that equation is .25q + .1d = 14.90. Let's solve the first equation for q. q = 80 - d. We can now use that as a substitution for q into the second equation, giving us an equation with only 1 unknown, d. .25(80-d) + .1d = 14.90. Distributing through the parenthesis we have 20 - .25d + .1d = 14.90. Combining like terms gives us - .15d = - 5.1. We will divide both sides by - .15 to get that the number of dimes is 34. If we had a total of 80 coins, then the number of quarters is 80 - 34, which is 46. 46 quarters and 34 dimes
23.
assuming you mean
first term is n=1, so 1²+3=1+3=4
2nd is n=2 so 2²+3=4+3=7
3rd is n=3 so 3²+3=9+3=12
the first 3 terms are 4,7,12
24.
5th term is 5²+3=25+3=28
10th term is 10²+3=100+3=103
difference is 103-28=75
1200 is the correct answer
