We have been given two points. $A(3,4)$ and $C(3,9)$ . We are asked to find the point B such that it divides line segment AC so that the ratio of AB to BC is 4:1.

We will use segment formula to solve our given problem.

When a point P divides segment any segment internally in the ratio $m:n$ , then coordinates of point P are:

$[\right x=\frac{mx_2+nx_1}{m+n},y=\frac{my_2+ny_1}{m+n}\left]$

$(x_1,y_1)=(3,4)$ and $(x_2,y_2)=(3,9)$ .

$m=4,n=1$

Upon substituting our given information in above formula, we will get:

$[\right x=\frac{4(3)+1(3)}{4+1},y=\frac{4(9)+1(4)}{4+1}\left]$

$[\right x=\frac{12+3}{5},y=\frac{36+4}{5}\left]$

$[\right x=\frac{15}{5},y=\frac{40}{5}\left]$

$[\right x=3,y=8\left]$

Therefore, the coordinates of point B would be $(3,8)$ .

8 0

3 years ago

I need help like Rn

igomit [66]

With
explanation; i gotcha

6 0

3 years ago

I dont understand my assignment<br>y+5x=6; x= -1,0,1

Setler79 [48]

I hope this helps you

5 0

3 years ago