The balanced net ionic equation for precipitation of caco3 when aqueous solutions of na2co3 and cacl2 are mixed is
1 answer:
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Answer:
The CSI is wrong.
Explanation:
1. Find the volume of the pool
The formula for the volume of a cylinder is V = πr²h .
D = 12 m; h = 10 m
r = D/2 = (12 m/2) = 6.0 m
V = πr²h = π × (6.0 m)² × 10 m = π × 36 m²× 10 m = 360π m³ = 1100 m³
= 1.1. × 10⁶ L
2. Calculate the moles of OH⁻
n = cV = 1.0 × 10⁻² mol·L⁻¹ × 1.3 × 10⁶ L = 11 000 mol of OH⁻
3. Calculate the moles of acetic acid needed for neutralization
HA + OH⁻ ⟶ A⁻ + H₂O
The molar ratio of is 1 mol HA:1 mol OH⁻, so you need 11 000 moL of acetic acid.
4. Calculate the actual moles of acetic acid
You have four 5 L jugs of acetic acid pH 2 .
Volume = 20 L
[H⁺] = 10⁻² mol·L⁻¹ = 0.01 mol·L⁻¹
(a) Set up an ICE table
HA + H₂O ⇌ A⁻ + H₃O⁺
I/mol·L⁻¹: c 0 0
I/mol·L⁻¹: - 0.01 +0.01 +0.01
I/mol·L⁻¹: c - 0.01 0.01 0.01
(b) Calculate the concentration of acetic acid
The concentration of the acetic acid is 6 mol·L⁻¹
(c) Calculate the moles of acetic acid
You have 100 mol of acetic acid.
The CSI is wrong.
You don't have enough acetic acid to neutralize the pool.
