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3 years ago

Plz help me with seven eight and nine

Chemistry

1 answer:

Nookie1986 [14]3 years ago

4 0

7 is atomic symbol 9 is atomic density 8 is the atomic number

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In the chemical reaction: 2 h 2 (g) o2 (g) → 2 h2o (g), with 8 grams of h 2 (2 grams/mole) and 16 grams of o2 (32 grams/mole) an

Shtirlitz [24]

Use stoichiometric ratio to determine which is in excess and which is limiting

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3 years ago

A student pipets 10 ml of a 0.0693 m solution of kbr into a 500 ml volumetric flask and dilutes to the mark. what is the concent

Sonja [21]

The initial concentration of solution is 0.0693 M. The volume of solution taken is 10 mL and it is diluted to a final volume of 500 mL.

According to dilution law, the product of initial concentration and volume is equal to the product of final concentration and volume as follows:

$C_{1}V_{1}=C_{2}V_{2}$

Here, $C_{1}$ is initial concentration, $C_{2}$ is final concentration, $V_{1}$ is initial volume and $V_{2}$ is final volume.

Rearranging to calculate final concentration,

$C_{2}=\frac{C_{1}\times V_{1}}{V_{2}}$

Putting the values,

$C_{2}=\frac{0.0693 M\times 10 mL}{500 mL}=0.001386 M$

Therefore, concentration of the resulting solution is 0.001386 M.

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3 years ago

In an acid-base neutralization reaction 38.74 ml of 0.500 m potassium hydroxide (ki) reacts with 50.00 ml of sulfuric acid solut

g100num [7]

Answer: 0.19M

Explanation: $2KOH+H_2SO_4\rightarrow K_2SO_4+2H_2O$

Using Molarity equation:

$n_1M_1V_1=n_2M_2V_2$

$M_1$ = molarity of acid

$V_1$ = volume of acid

$M_2$ = molarity of base

$V_2$ = volume of base

$2\times M_1\times 50ml=1\times 0.500M\times 38.74ml$

$M_1=0.19M$

Thus the concentration of the $H_2SO_4$ solution is 0.19M.

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3 years ago

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3) Summarize the ways the desert can help preserve a body.

Elena-2011 [213]

3. Historically, bodies have been preserved naturally through freezing, cold or dry heat or, in the right climate, through burial in a particular type of soil.
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3 years ago

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The answer is C

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2 years ago