Answer:
v=9i+3j
Step-by-step explanation:
The given vector, v has initial point at P1 = (−5, −2) and terminal point at P2 = (4, 1).
The vector v is found by subtraction the initial point from the terminal point.
v=<4,1>-<-5,-2>
v=<4--5,1--2>
v=<9,3>
We write v as multiples of the basis vectors to obtain:
v=9i+3j
<span>5 = 15
---------
8 = x
cross multiply
5x =120
5x÷5 = 120÷5
x = 24
Check
5/8 = 15/24
.625 = .625
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Change in y over change in x
Answer:
25
Step-by-step explanation:
Answer:
( x + 2 ) and ( x - 11 )
Step-by-step explanation:
x² - 9x - 22 = 0
x² + 2x - 11x - 22 = 0
x ( x + 2 ) - 11 ( x + 2 ) = 0
( x + 2 ) ( x - 11 ) = 0
Factors of x² - 9x - 22 are ( x + 2 ) and ( x - 11 ).