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Galina-37 [17]
3 years ago
8

The universally accepted film size for movies has a width of 35 millimeters. If you want to project a movie onto a square sheet

that has an area of ​​100 square meters, what is the scale factor that is needed for the projection of the movie? Explain
Mathematics
1 answer:
dlinn [17]3 years ago
6 0

Answer:

<h2>The scale factor is 285.7143 ≅ 286.</h2>

Step-by-step explanation:

The square sheet has an area of 100 square meters.

Hence, the width of the sheet is \sqrt{100} = 10 meters.

The scale factor is needs to be in such a way, so that the film's wide will be match perfectly with the square sheet. Hence, 35x millimeters = 10 meters = 10000 millimeters .

x = \frac{10000}{35} = 285.7143.

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Simplify the radical expression
denis-greek [22]

Answer:

6x

Step-by-step explanation:

\sqrt{36 {x}^{2} }  =  \sqrt{36}  \times  \sqrt{ {x}^{2} }

Square of 36 is 6. Square of x^2is x.

6x

3 0
2 years ago
The first three terms of an arithmetic sequence are as follows
ozzi

Answer:

32 and 39

Step-by-step explanation:

The common difference d for the sequence is 7

1st term of the sequence a1 is 11.

4th (a4) and 5th  (a5) term of the sequence are required

nth term of an arithmetic sequence an =a1+(n-1)d

a4=11+(4-1)7=32

a5=11+(5-1)7=39

4 0
3 years ago
Find the range of the parent function below y=x^2
marusya05 [52]

you don't show the graph, but graphing y=x^2 it is a U shaped line that starts at (0,0) and the lines go upwards on both sides of the Y axis,

 This means all real numbers above 0 and 0 will solve it

 so the range is y≥0

6 0
3 years ago
How many solutions does the equation y=3x have?
Butoxors [25]

Answer:

1 solution

Step-by-step explanation:

If you were to graph this line it would be a straight line so there is 1 solution.

y=3x

x=y/3

7 0
2 years ago

jekas [21]

Given: In the given figure, there are two equilateral triangles having side 50 yards each and two sectors of radius (r) = 50 yards each with the sector angle θ = 120°

To Find: The length of the park's boundary to the nearest yard.

Calculation:

The length of the park's boundary (P) = 2× side of equilateral triangle + 2 × length of the arc

or,                    (P) = 2× 50 yards + 2× (2πr) ( θ ÷360°)

or,                    (P) = 2× 50 yards + 2× (2×3.14× 50 yards) ( 120° ÷360°)

or,                    (P) = 100 yards + 2× (2×3.14× 50 yards) ( 120° ÷360°)

or,                    (P) = 100 yards + 209.33 yards

or,                    (P) = 309.33 yards ≈309 yards

Hence, the option D:309 yards is the correct option.

7 0
3 years ago
Read 2 more answers
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