The length of a rectangle is 4 cm less than twice the width. express as an integer the maximum width of the rectangle when the perimeter is less than 78 cm.
Answer:
2(k+5)
Step-by-step explanation:
Factor 2k+10
2k+10
=2(k+5)
Answer:
2(k+5)
Answer:
А.The system has two solutions, but only one is viable because the other results in a negative width.
Step-by-step explanation:
Given
Let:
length of play area A
width of play area A
length of play area B
width of play area B
Area of A
Area of B
From the question, we have the following:




The area of A is:

This gives:

Open bracket

The area of B is:


Substitute: 

Open brackets


Expand


We have that:

This gives:

Collect like terms


Using quadratic calculator, we have:
or
--- approximated
But the width can not be negative; So:

Answer:
<h2>y = -5/4x -8</h2>
Step-by-step explanation:

Answer:
they are equivalent
Step-by-step explanation:
simplifying 12r + p -4r + 6p you get 8r + 7p
so yes they are equal