Question

Jorge has a bag containing 3 red coins and 3 black coins.He pickes a coin from the bag, looks at the color, and does not replace the coins. Jorge then picks another coin from the bag. What is the probability that he will choose a black coin first and a black coin second?

Answer 1

Answer:

Probability of picking a black coin in the first and second collection without replacement = 1/5

Step-by-step explanation:

Probability that he'll pick a black coin in the first and second selection =

3/6 × 2/5 = 6/30 = 1/5

Answer 2

Answer:

1/5

Step-by-step explanation:

The question says that 3 blacks coins are in a bag as well as 3 red coins.

A coin is picked at random without replacement and another coin is picked again.What is the probability of both coins picked been a black.

P(B)= 3/6 which is also 1/2

Probability of second coin picked been black again will be

P(B) = 2/5( if one coins is picked and not replaced the total number of coins left will reduce)

Therefore,the probability of this happening will be

1/2×2/5= 1/5