Ay2(6y-11) - b (6y+11)
multiply
12ay6^2 - 22ay - 6by +10b
Answer: 6/11
Step-by-step explanation:
28 - 7 = 21
16 + 11 - 21 = 6
11 - 6 = 5
16-6 = 10
10 + 5 15
P (a) = 16/28
p (b) = 11/28
A I B = 6/28/11/28 = 6/11
Answer:
The ball will be at 100 feet at time x=0.5 sec and at time x=7.5 sec
Step-by-step explanation:
<u><em>The correct question is</em></u>
A ball is launched upward from a height 40 feet above ground level. the ball's height at t seconds is given by h(t)=-16t^2+128t+40 At what time(s) will the ball be at 100 feet?
we have

so
For h(t)=100 ft
substitute in the equation and solve for x


The formula to solve a quadratic equation of the form
is equal to
in this problem we have

so
substitute in the formula
therefore
The ball will be at 100 feet at time x=0.5 sec and at time x=7.5 sec
Answer:
slope:2
Step-by-step explanation:
Slope is rise/run, or change in y/change in x.
With that being said, we only need two points to solve this.
Let's take the points (0,7) and (1,9)
The formula for finding the slope from two points is m=(y2-y1)/(x2-x1).
M is the slope.
y2 would be the y-value of the second point,9. y1 would be the y-value of the first point, 7.
x2 would be the x-value of the second point, 1. x1 would be the x-value of the first point, 0.
Plugging those values in to the formula, we get m=(9-7)/(1-0)
Simplifying, we get m=2/1, which is m=2.
Answer: 6
Step-by-step explanation:
take 8-2 =6