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Sergeu [11.5K]
3 years ago
6

Can someone help me with a math problem

Mathematics
1 answer:
Veronika [31]3 years ago
7 0
First, you would start by adding 7 8/15 and 11 1/6 together. Starting with the whole numbers you would add 7 and 11, getting 18. You would then multiply 8/15 by 2/2 and 1/6 by 5/5, making them 16/30 and 5/30, you then add them getting 21/30, or 7/10. Then add 18 and 7/10 together, getting 18 7/10. Finally, subtract 13 1/6 from 18 7/10. You would start by subtracting 13 from 18, getting 5. Then you would multiply 1/6 by 5/5 and 7/10 by 3/3, getting 5/30 and 21/30, you would subtract 5/30 from 21/30, getting 16/30. Finally, you would add 16/30 and 5 with each other, getting 5 16/30.
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DerKrebs [107]

Answer:

y = -1/3x + 5

Step-by-step explanation:

y = mx + b

so y = 3, x = 6, m = -1/3

then 3 = (-1/3)6 + b

3 = -2 + b

b = 5

so y = -1/3x + 5

5 0
2 years ago
Is this answer right?
zalisa [80]

Answer:

yes I think so

Step-by-step explanation:

5 0
3 years ago
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Pls help I’m so confused
solniwko [45]

Answer:

Yes

Step-by-step explanation:

First, look for the hypotenuse (diagonal) of the base of the box. We have the two legs: 13 inches and 35 inches.

Set up an equation using the Pythagorean theorem:

13^2+35^2=C^2

Solve for C:

169 + 1225 = C^2

1394 = C^2

C ≈ 37.34

Now that we have the diagonal of the base, we know can move on to find the value of the interior diagonal. We have two legs: 13 inches and 37.34 inches.

Again, set up an equation using the Pythagorean theorem, and solve for the new C:

13^2+37.34^2=C^2

1563.2756 = C^2

C = 39.54

The interior diagonal of the box is approximately 39.54 inches long, which is longer than Kylie's baton, which is 38 inches long. So, she can fit the baton in the box.

Have a nice day! :)

7 0
2 years ago
Suppose the number of births that occur in a hospital can be assumed to have a Poisson distribution with parameter = the average
arsen [322]

Answer:

0.5372

Step-by-step explanation:

Given that the number of births that occur in a hospital can be assumed to have a Poisson distribution with parameter = the average birth rate of 1.8 births per hour.

Let X be the no of births in the hospital per hour

X is Poisson

with mean = 1.8

the probability of observing at least two births in a given hour at the hospital

= P(X\geq 2)\\= 1-F(1)\\= 1-0.4628\\= 0.5372

the probability of observing at least two births in a given hour at the hospital = 0.5372

4 0
3 years ago
How are gallons and fluid ounces related
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They both are a type of measurement
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3 years ago
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