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Rasek [7]
3 years ago
8

Hurry I'm timed !!!pleas

Mathematics
1 answer:
shepuryov [24]3 years ago
3 0

Answer:

A. whole numbers, integers , rational numbers, natural numbers, real numbers

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Factor the expression using the GCF. A. 2(4a + 8c) B. 4(2a + 4c) C. 8(a + 2c) D. 16( 12 a + c) Not multiple choice
dimulka [17.4K]

Note: The expression is missing. Consider the expression is 8a+16c.

Given:

The expression is

8a+16c

To find:

Factor form of the given expression by using GCF.

Solution:

We have,

8a+16c

Factors of each term:

8a=2\times 2\times 2\times a

16c=2\times 2\times 2\times 2\times c

The common factors are 2, 2 and 2. So,

GCF(8a+16c)=2\times 2\times 2

GCF(8a+16c)=8

Taking out the greater common factor (GCF) in the given expression, we get

8a+16c=8(a+2c)

Therefore, the required expression is 8(a+2c) and the correct option is C.

5 0
3 years ago
What is the value of y when x = 4?<br> y=15x+7
Nana76 [90]

Answer: Y= 67

Step-by-step explanation:

The equation says;

Y= 15x + 7

When x=4

We have Y= 15(4)+7 by substituting the value of x for the equation. So, we have

Y=60+7

Y= 67

3 0
4 years ago
Brainliest and 50 points! Data picture is added below
Semmy [17]

Answer/Step-by-step explanation:

A. The cluster is where the 100 is to the 235. The outlier is 1,110 cause it is way out in the open alone almost 300 numbers away from its nearest number

B. For the correlation if you notice how it goes from 200... > 400...> 600...>800...it kinda like a pattern of  adding 200

C. The independent variable  is temperature and the dependent is sales. since the amount of money made depends on the temperature.

Download docx
8 0
3 years ago
Explain how you find instantaneous velocity and find it for s(t) = -3 + 4t^2 when t = 5 seconds.
White raven [17]
You take the derivative of the position equation  s(t) = -3 + 4t^{2}
and you get  v(t) = 8t
now plug in 5 
v(5) = 40
40 m/s is your answer

5 0
3 years ago
If f and t are both even functions, is the product ft even? If f and t are both odd functions, is ft odd? What if f is even and
Natali5045456 [20]

Answer:

(a) If f and t are both even functions, product ft is even.

(b) If f and t are both odd functions, product ft is even.

(c) If f is even and t is odd, product ft is odd.

Step-by-step explanation:

Even function: A function g(x) is called an even function if

g(-x)=g(x)

Odd function: A function g(x) is called an odd function if

g(-x)=-g(x)

(a)

Let f and t are both even functions, then

f(-x)=f(x)

t(-x)=t(x)

The product of both functions is

ft(x)=f(x)t(x)

ft(-x)=f(-x)t(-x)

ft(-x)=f(x)t(x)

ft(-x)=ft(x)

The function ft is even function.

(b)

Let f and t are both odd functions, then

f(-x)=-f(x)

t(-x)=-t(x)

The product of both functions is

ft(x)=f(x)t(x)

ft(-x)=f(-x)t(-x)

ft(-x)=[-f(x)][-t(x)]

ft(-x)=ft(x)

The function ft is even function.

(c)

Let f is even and t odd function, then

f(-x)=f(x)

t(-x)=-t(x)

The product of both functions is

ft(x)=f(x)t(x)

ft(-x)=f(-x)t(-x)

ft(-x)=[f(x)][-t(x)]

ft(-x)=-ft(x)

The function ft is odd function.

7 0
3 years ago
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