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Tomtit [17]
3 years ago
9

Given ΔDEF : ΔRST, find the scale factor.

Mathematics
2 answers:
LekaFEV [45]3 years ago
8 0

Answer:  The value of x is 12 units and the scale factor is \dfrac{4}{3}.

Step-by-step explanation:  Given that the triangle DEF is similar to the triangle RST.

We are to find the value of x and the scale factor of the dilation.

We know that the corresponding sides of the similar triangles are proportional.

So, we must have

\dfrac{DE}{RS}=\dfrac{EF}{ST}\\\\\\\Rightarrow \dfrac{3}{x}=\dfrac{4}{16}\\\\\\\Rightarrow \dfrac{3}{x}=\dfrac{1}{4}\\\\\Rightarrow x=3\times4\\\\\Rightarrow x=12.

The scale factor is given by

S=\dfrac{\textup{length of a side of the dilated triangle}}{\textup{length of the corresponding side of the original triangle}}\\\\\\\Rightarrow S=\dfrac{RS}{DE}\\\\\\\Rightarrow S=\dfrac{4}{3}.

Thus, the value of x is 12 units and the scale factor is \dfrac{4}{3}.

Grace [21]3 years ago
5 0
The scale factor of DEF : RST is 3/4.

X = 12
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LiRa [457]
A triangle has 3 angles.

The sum of the measures of the angles of a triangle is 180.

In an equilateral triangle, all angles have the same measure.

180/3 = 60

Answer: 60 degrees.

7 0
3 years ago
PLEASE HELP!!!! WILL GIVE BRAINLIEST!!!!<br><br><br><br><br><br> Only need 4b and 4c
JulsSmile [24]

ANSWER:

b) No

c) Yes

EXPLANATION:

3 (x+1)=3x+3

b)

3 (-8 + 1) = 3 x -8 + 3

(3 x -8) (3 x +1) = 3 x -8 + 3     (just put left and right sides into calcu separately)

-72 = -21

Both sides are not equal and therefore it isn't a solution.

c)

3 (0.5 + 1) = 3 x 0.5 + 3

(3 x 0.5) (3 x +1) = 3 x 0.5 + 3

4.5 = 4.5

Both sides are equal and thereofre it IS a solution.

6 0
3 years ago
Sergio makes belts in his garage.He makes a certain number of belts for every hour he works.what is the missing value in the tab
aleksklad [387]
Is 12 Because the pattern is 2+1=3; 4+2=6;
6+3=9; 8+4=12 and 10+5=15
8 0
3 years ago
A nursery has two hundred 7-gallon palm trees to sell, consisting of coconut palm trees, saw palmetto palm trees and christmas p
motikmotik

Total number of trees available to be sold = 200

Selling price of coconut palm trees sell (Pco)= $75 each

Selling price of saw palmetto palm trees sell (Pp) = $45 each

Selling price of christmas palm trees (Pch) = $30 each

Number of saw palmetto palm trees (Np) = 3 × Number of christmas palm trees (Nch)

Let number of coconut palm trees be Nco

Total price paid by developer for all the palm trees = 12,300

So Total number of trees = Nco + Np + Nch

⇒ 200 = Nco + 3×Nch + Nch

⇒ 200 = Nco + 4Nch ................ (i)

Total selling price of trees = Sco × Nco + Sp × Np + Sch × Nch

⇒ 12,300 = 75×Nco + 45×Np + 30×Nch

Dividing above equation by 5

⇒ 2,460 = 15Nco + 9Np + 6Nch

Substituting Np = 3Nch in the above equation

⇒ 2,460 = 15Nco + 9 (3Nch) + 6Nch

⇒ 2,460 = 15Nco + 33Nch ................ (ii)

Mutiply (i) with 15 and subtract from (ii)

⇒ 2,460 - 3,000 = 15Nco + 33Nch - 15Nco - 60Nch

⇒ -540 = 33Nch - 60Nch

⇒ -540 = 27Nch

⇒ Nch=20

If Nch = 20, Np = 3×20 = 60

Since Nco + Np + Nch = 200

⇒ Nco = 200 - (80)

⇒ Nco = 120

Hence, the developer purchased 120 coconut palm trees, 20 christmas palm trees and 60 saw palmetto palm trees.

6 0
3 years ago
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Vsevolod [243]

The answer is 4/5 all you do is rise over run

5 0
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