Ask question

Ask question

All categories

3 years ago

8

Joan decided to look at new SUVs.Joan found a used SUV for$6000.Joan found that she paid 25% of the price of a new SUV . How muc

h would a new SUV cost.

1 answer:

UNO [17]3 years ago

3 0

A new SUV would cost $24,000 because 25% is 1/4 , so $6,000 times 4 =$24,000

You might be interested in

What is the length of the midsegment of this trapezoid?<br><br> Enter your answer in the box.

hichkok12 [17]

I believe it is 8 because $EF= \frac{AB+CD}{2} = EF= \frac{5+11}{2} =8$

4 0

3 years ago

Read 2 more answers

Solve the following absolute value equations. Show the solution set and check your answers. |0.3-3/5k|-0.4=1.2

9966 [12]

Answer:

**The equation is not clear, so I have provided both options**

<h3><u>Option 1</u></h3>

$\left|0.3-\dfrac{3}{5}k\right|-0.4=1.2$

$\implies \left|0.3-\dfrac{3}{5}k\right|=1.6$

<u>Solution 1</u>

$\implies 0.3-\dfrac{3}{5}k=1.6$

$\implies -\dfrac{3}{5}k=1.3$

$\implies k=-\dfrac{13}{6}$

<u>Solution 2</u>

$\implies -(0.3-\dfrac{3}{5}k)=1.6$

$\implies -0.3+\dfrac{3}{5}k=1.6$

$\implies \dfrac{3}{5}k=1.9$

$\implies k=\dfrac{19}{6}$

<h3><u>Option 2</u></h3>

$\left|0.3-\dfrac{3}{5k}\right|-0.4=1.2$

$\implies \left|0.3-\dfrac{3}{5k}\right|=1.6$

<u>Solution 1</u>

$\implies 0.3-\dfrac{3}{5k}=1.6$

$\implies -\dfrac{3}{5k}=1.3$

$\implies -3=6.5k$

$\implies k=-\dfrac{6}{13}$

<u>Solution 2</u>

$\implies -(0.3-\dfrac{3}{5k})=1.6$

$\implies -0.3+\dfrac{3}{5k}=1.6$

$\implies \dfrac{3}{5k}=1.9$

$\implies 3=9.5k$

$\implies k=\dfrac{6}{19}$

6 0

1 year ago

Soap films and bubbles are colorful because the interference conditions depend on the angle of illumination (which we aren't cov

mylen [45]

Answer:

56.39 nm

Step-by-step explanation:

In order to have constructive interference total optical path difference should be an integral number of wavelengths (crest and crest should be interfered). Therefore the constructive interference condition for soap film can be written as,

$2t=(m+\frac{1}{2} ).\frac{\lambda}{n}$

where λ is the wavelength of light and n is the refractive index of soap film, t is the thickness of the film, and m=0,1,2 ...

Please note that here we include an additional 1/2λ phase shift due to reflection from air-soap interface, because refractive index of latter is higher.

In order to have its longest constructive reflection at the red end (700 nm)

$t_1=(m+\frac{1}{2} ).\frac{\lambda}{2.n}\\ \\ t_1=\frac{1}{2} .\frac{700}{(2)*(1.33)}\\ \\ t_1=131.58\ nm$

Here we take m=0.

Similarly for the constructive reflection at the blue end (400 nm)

$t_2=(m+\frac{1}{2} ).\frac{\lambda}{2.n}\\ \\ t_2=\frac{1}{2} .\frac{400}{(2)*(1.33)}\\ \\ t_2=75.19\ nm$

Hence the thickness difference should be

$t_1-t_2=131.58-75.19=56.39 \ nm$

7 0

2 years ago

dentify all of the following solutions of square root of x minus 8 end root plus 8 equals x. (1 point)

viva [34]

Answer:gh

Step-by-step explanation:

3 0

2 years ago

2. The long-jump pit was recently rebuilt to make it level with the runway. Volunteers provided pieces of

lakkis [162]

Answer:2. It’s 24.58

How many boards did the volunteers supply round your calculations to the nearest hundred- 13.44

How many whole boards-14

Step-by-step explanation:

8 0

2 years ago