----------------------------------------------------------------------------------------------
Find the duration
----------------------------------------------------------------------------------------------
Time : 9:00am to 10:15am
Duration: 1hour 15 mins or 1.25hours
----------------------------------------------------------------------------------------------
Find difference in distance travelled between the two cyclists.
----------------------------------------------------------------------------------------------
Difference in speed = 6km/h
1 hour = 6 km
1.25 hours = 7.5km
----------------------------------------------------------------------------------------------
Find the distance the cyclist traveled
----------------------------------------------------------------------------------------------
42.5 - 7.5 = 35km
35km ÷ 2 = 17.5km
The slower cyclist traveled 17.5 km in the 1.25 hours
17.5 + 7.5 = 25 km
The faster cyclist traveled 25km in the 1.25 hours
----------------------------------------------------------------------------------------------
Find the speed of the slower cyclist
----------------------------------------------------------------------------------------------
1.25 hour = 17.5 km
1 hour = 17.25 ÷ 1.25
1 hour = 14km
The cyclist was traveling at 14km/h
----------------------------------------------------------------------------------------------
Find the speed of the faster cyclist
----------------------------------------------------------------------------------------------
1.25 hour = 25km
1 hour = 25 ÷ 1.25
1hour = 20 km
The cyclist was traveling at 20km/hour
----------------------------------------------------------------------------------------------
Answer: The speed were 14km/h and 20 km/h
----------------------------------------------------------------------------------------------
Let's say the ratio is 3:4. It could be written as 3/4
Step-by-step explanation:
Wow that's sad sir..
Hope it gets better ;-;
Answer:
Problem 1) frequency: 160 heartbeats per minute, period= 0.00625 minutes (or 0.375 seconds)
Problem 2) Runner B has the smallest period
Problem 3) The sound propagates faster via a solid than via air, then the sound of the train will arrive faster via the rails.
Step-by-step explanation:
The frequency of the football player is 160 heartbeats per minute.
The period is (using the equation you showed above):

second problem:
Runner A does 200 loops in 60 minutes so his frequency is:
loops per minute
then the period is: 0.3 minutes (does one loop in 0.3 minutes)
the other runner does 200 loops in 65 minutes, so his frequency is:
loops per minute
then the period is:

Therefore runner B has the smaller period