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denpristay [2]
3 years ago
12

What is 9 over 5 in a percent

Mathematics
2 answers:
Nataly_w [17]3 years ago
3 0
So you convert the fraction into a decimal then multiply it by 100 so the percentage would be 180%
aev [14]3 years ago
3 0
180% is 9/5 as a percent
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Right Triangle Trigonometry.
DiKsa [7]

Answer:

D

Step-by-step explanation:

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2 years ago
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The difference of three times a number and six is nine
Artyom0805 [142]

Answer:

3x-6=9 is your equation x=5

Step-by-step explanation:

Step 1: Add 6 to both sides

Step 2: Divide both sides by 3

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3 years ago
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Find all of the points of the form (x −1) which are 4 unit from the point (3,2)
Bond [772]

Answer:

(3+2\sqrt{2},2+2\sqrt{2}),(3-2\sqrt{2},2-2\sqrt{2})

Step-by-step explanation:

Points\ are\ of\ the\ form\ (x,x-1)\\\\Distance\ of\ these\ points\ from\ (3,2)=4\\\\\sqrt{(x-3)^2+(x-3)^2}=4\\\\\sqrt{(x-3)^2+(x-1-2)^2}=4\\\\\sqrt{2(x-3)^2}=4\\\\2(x-3)^2=16\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ square\ both\ the\ sides\\\\(x-3)^2=\frac{16}{2}\\\\(x-3)^2=8\\\\(x-3)=\pm 2\sqrt{2}\ \ \ \ \ \ \ \ \ \ \ square\ root\ both\ the\ sides\\\\x=3\pm 2\sqrt{2}\\\\When\ x=3+2\sqrt{2}\ \ \Rightarrow x-1=3+2\sqrt{2}-1=2+2\sqrt{2}\\\\When\ x=3-2\sqrt{2}\ \ \Rightarrow x-1=3-2\sqrt{2}-1=2-2\sqrt{2}

4 0
3 years ago
Help ASAP
kipiarov [429]

Answer:round to the nearest tenth

Step-by-step explanation:

6 0
2 years ago
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Under a certain transformation T, AA'BC' is the image of AABC. The perimeter of AA'B'C' is twice the perimeter of ABC. What kind
Anika [276]

The dimensions of the image are twice the dimensions of the preimage,

which indicates that the transformation is a dilation.

  • The transformation <em>T</em> is; <u>a dilation transformation with a scale factor of 2, D₂</u>

Reasons:

The transformation applied to ΔABC = T

The image of ΔABC following the transformation, T = ΔA'B'C'

The perimeter of ΔA'B'C' = Twice the perimeter of ΔABC

Therefore, we have;

A'B' + B'C' + A'C' = 2 × (AB + BC + AC)

Which gives

A'B' + B'C' + A'C' = 2·AB + 2·BC + 2·AC

By similar triangles, we have the ratio of corresponding sides as follows;

\displaystyle \frac{AB}{A'B'}  = \frac{BC}{B'C'} = \mathbf{ \frac{AC}{A'C'}}

Which gives;

\displaystyle \frac{AB}{A'B'}  = \frac{AB}{2 \cdot AB} = \frac{1}{2}

A'B' = 2·AB

Therefore;

  • Triangle ΔA'B'C' is twice the dimension of triangle ΔABC, and <em>T</em> is <u>a dilation transformation with a scale factor of 2, D₂</u>

Learn more about dilation transformation here:

brainly.com/question/2458912

3 0
2 years ago
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