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3 years ago

Which graph shows the solution set of x-1/1-x<0

Mathematics

2 answers:

Licemer1 [7]3 years ago

8 0

Answer:

answer b

Step-by-step explanation:

LekaFEV [45]3 years ago

6 0

Answer:

the correct answer is C

Step-by-step explanation:

just did it on edg 2020 :)

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Solve by elimination <br> 5x-y=12 <br> 3x+2y=2

Ber [7]

(2)5x-y=12
3x+2y=2
10x-2y=12
3x+2y=2
13x=2
x=0.15

7 0

3 years ago

Read 2 more answers

Please answer this question

ICE Princess25 [194]

Answer:

A: 77

Step-by-step explanation:

360 - 109 - 137 - 37 = 77

3 0

2 years ago

Evaluate the integral. (sec2(t) i t(t2 1)8 j t7 ln(t) k) dt

polet [3.4K]

If you're just integrating a vector-valued function, you just integrate each component:

$\displaystyle\int(\sec^2t\,\hat\imath+t(t^2-1)^8\,\hat\jmath+t^7\ln t\,\hat k)\,\mathrm dt$

$=\displaystyle\left(\int\sec^2t\,\mathrm dt\right)\hat\imath+\left(\int t(t^2-1)^8\,\mathrm dt\right)\hat\jmath+\left(\int t^7\ln t\,\mathrm dt\right)\hat k$

The first integral is trivial since $(\tan t)'=\sec^2t$ .

The second can be done by substituting $u=t^2-1$ :

$u=t^2-1\implies\mathrm du=2t\,\mathrm dt\implies\displaystyle\frac12\int u^8\,\mathrm du=\frac1{18}(t^2-1)^9+C$

The third can be found by integrating by parts:

$u=\ln t\implies\mathrm du=\dfrac{\mathrm dt}t$

$\mathrm dv=t^7\,\mathrm dt\implies v=\dfrac18t^8$

$\displaystyle\int t^7\ln t\,\mathrm dt=\frac18t^8\ln t-\frac18\int t^7\,\mathrm dt=\frac18t^8\ln t-\frac1{64}t^8+C$

8 0

3 years ago

What property says that -12+12+0

natali 33 [55]

Answer:

Looks like <u>inverse property of addition </u>to me

4 0

3 years ago

Convert each percentage into a decimal and match them with the appropriate result.

skad [1K]

Answer:

32% = 0.32

50% = 0.50

34% = 0.34

Step-by-step explanation:

0.32 = 32%

0.50 = 50%

0.34 = 34%

P.S Can I have brainliest?

5 0

2 years ago

Read 2 more answers