Step-by-step explanation:
al nth term:
numerator:
denominator:
so nth term :
b). 1; 11; 27; 49
first difference: 10; 16; 22
second difference :6
formula for 1st difference:3a+b
formula for 2nd difference:2a
Therefore:
2a=6
a=3
3a+b=10
sub in a
3(3)+b=10
9+b=10
b=1
sub into quadratic formula
So Tn:
Answer:
20 20/27
Step-by-step explanation:
(2 2/3)(3 1/3)(2 1/3) = (8/3)(10/3)(7/3) = 560/27 = 20 20/27
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<em>Additional comment</em>
The first two numbers can be written as a difference and a sum:
= (3 -1/3)(3 +1/3)(2 1/3)
= (3·3 -1/3·3 +3·1/3 -1/3·1/3)(2 1/3)
= (9 -1/9)(2 +1/3) = 9·2 +9·1/3 -1/9·2 -1/9·1/3 = 18 +3 -6/27 -1/27
= 20 20/27
The GCF would be 14a, because 14a x 1 = 14a, and 14a x 2b = 28ab.
You’re going it plug in the inputs for every input for the letter x. So the first one, fx= -4(-2)+1= 9. The second one fx= -4(0)+1=1. The third one fx= -4(5)+1=19.
