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3 years ago

The diagonals of a square are

Mathematics

1 answer:

sammy [17]3 years ago

8 0

The answer to this is B

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Karen has 4h storyboiks. Karen's storybook collection is 2/3 of what Mary's collection is. How many storybooks do they have in a

Dafna11 [192]

In order to find out the answer , you just need to count :
Let's say that mary's collection is symbolized by x

2/3 x = 4h

x = 3/2 . 4h

x = 6h

The storybooks they have in total would be : 6h + 4h = 10 h

hope this helps

6 0

3 years ago

Please help me because I’m dying literally dying

nevsk [136]

perimeter or rectangle= 2l+2w

Surface area of a cylinder=2(pi)r^2+2(pi)r

Volume of a triangular prism=Bh

Area of a circle=(pi)r^2

6 0

3 years ago

Read 2 more answers

1) Use power series to find the series solution to the differential equation y'+2y = 0 PLEASE SHOW ALL YOUR WORK, OR RISK LOSING

iogann1982 [59]

$y=\displaystyle\sum_{n=0}^\infty a_nx^n$

then

$y'=\displaystyle\sum_{n=1}^\infty na_nx^{n-1}=\sum_{n=0}^\infty(n+1)a_{n+1}x^n$

The ODE in terms of these series is

$\displaystyle\sum_{n=0}^\infty(n+1)a_{n+1}x^n+2\sum_{n=0}^\infty a_nx^n=0$

$\displaystyle\sum_{n=0}^\infty\bigg(a_{n+1}+2a_n\bigg)x^n=0$

$\implies\begin{cases}a_0=y(0)\\(n+1)a_{n+1}=-2a_n&\text{for }n\ge0\end{cases}$

We can solve the recurrence exactly by substitution:

$a_{n+1}=-\dfrac2{n+1}a_n=\dfrac{2^2}{(n+1)n}a_{n-1}=-\dfrac{2^3}{(n+1)n(n-1)}a_{n-2}=\cdots=\dfrac{(-2)^{n+1}}{(n+1)!}a_0$

$\implies a_n=\dfrac{(-2)^n}{n!}a_0$

So the ODE has solution

$y(x)=\displaystyle a_0\sum_{n=0}^\infty\frac{(-2x)^n}{n!}$

which you may recognize as the power series of the exponential function. Then

$\boxed{y(x)=a_0e^{-2x}}$

7 0

3 years ago

Which statement is true?

riadik2000 [5.3K]

Answer:

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

PLEASE HELP 20 POINTS!! QUESTION IS AN IMAGE

prisoha [69]

Okay, so first off, if you need to graph anything, I suggest Desmos, it's a website with an online graphing calculator. It saved my life for highschool geometry.

Now, to answer your question, your y-intercept is going to be at point (0,2). Your x-intercepts are going to be at points (-2,0) and (-4,0). Your point is at (-3,-1). And then your lines simply extend from there.

Hope this isn't too late to be helpful, good luck with your assignments.

5 0

2 years ago