Answer:
3√2 or 4.24
Step-by-step explanation:
d(w,x) = √(5-2)² + (-4-(-7))² = √18 = 3√2 (4.24)
X-int: (square root of 31 + 6,0) & (square root of 31-6,0)
Y-int: (0,5)
Vertex: (6,-31)
AOS: x=6
Max/Min Value: (6,-31)
The mass of substance left after 7 days is 13.09 g
The mass of substance left, N is given by
N = N₀exp(-λt) where λ = decay constant and N₀ = initial mass of substance present = 24 g and t = time
Also, λ = 0.693/t' where t' = half-life of iodine = 8 days
So, λ = 0.693/t'
λ = 0.693/8
λ = 0.086625/day
Since the mass of substance left is N = N₀exp(-λt) and we require the mass of substance after t = 7 days,
N = N₀exp(-λt)
N = 24 gexp(-0.086625/day × 7 days)
N = 24 gexp(-0.606375)
N = 24 g × 0.5453
N = 13.09 g
So, the mass of substance left after 7 days is 13.09 g
Learn more about radioactive decay here:
brainly.com/question/23705307
Givens
Let the number of students in the class be x
Let the number of pieces of gum she gave out be 3x
Equation
3x + 8 = 168 This will not work out evenly. Let's try x - 1. The reason for that is because she may not give out anything to herself.
3(x - 1) + 8 = 168 This doesn't work either.
Well we have to choose. It's a rounding problem.
3x + 8 = 168 Subtract 8 from both sides.
3x = 168 - 8 Combine
3x = 160 Divide by 3 on both sides.
x = 160 / 3
x = 53.333333333
Since that can't be, we could say there were 53 students.
3x
Answer:
11 feet
Step-by-step explanation:
Squares have the same length and width. So you just take the square root of teh area to find both.
√121 = 11
