What is the average rate of change of the function fx= 2x2+ 3 over the interval [1,4]?
1 answer:
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Write the first trigonometric expression in terms of the second expression.
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Answer:
(r o g)(2) = 4
(q o r)(2) = 14
Step-by-step explanation:
Given
Solving (a): (r o q)(2)
In function:
(r o g)(x) = r(g(x))
So, first we calculate g(2)
Next, we calculate r(g(2))
Substitute 9 for g(2)in r(g(2))
r(q(2)) = r(9)
This gives:
{
Hence:
(r o g)(2) = 4
Solving (b): (q o r)(2)
So, first we calculate r(2)
Next, we calculate g(r(2))
Substitute 3 for r(2)in g(r(2))
g(r(2)) = g(3)
Hence:
(q o r)(2) = 14